Constructor two classes up java

Question

I am trying to access a constructor in an abstract class that is two levels higher.

    public abstract class Person{
        protected String name;

    public Person(String name){
         if name.length() <= 12)
            this.name = name;
         else 
            this.name = name.substring(0,12);
    }

    public final String returnName(){
       return name;
    }
   }

public class employee extends person{

        public employee(string firstname, string gender){
               super(firstname);
               this.gender =gender;
         }

}

public class dependent extends employee{

        public dependent(string firstname, string gender, string relation){
             super(firstname);
             super(gender);
             this.relation = relation;
        }

How do I invoke the constructor of the abstract class from the dependent class (two levels below)?

your code will not even compile try it again. it wont even compile. — Kishan Bheemajiyani, Nov 18 '14 at 05:29
You don't have a constructor for super(gender) it would be super (firstname,gender) — Kenneth Clark, Nov 18 '14 at 05:29
This has been asked before. You can't skip the "in between" class - you have to call one of the constructors of `employee` from within `dependent`. Fortunately, there is a suitable one there for you, in this case. — Dawood ibn Kareem, Nov 18 '14 at 05:32

Mailkov · Answer 1 · 2014-11-19T09:35:47.483

0

try this:

public class employee extends Person{

        public employee(String firstname, String gender){
               super(firstname);
               this.gender =gender;
         }

}

public class dependent extends employee{

        public dependent(String firstname, String gender, String relation){
             super(firstname,gender);
             this.relation = relation;
        }

edited Nov 19 '14 at 09:35

answered Nov 18 '14 at 05:32

Mailkov

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score 0 · Answer 2 · answered Nov 18 '14 at 05:33

Ok, first of all, here's how you pass two parameters to your Employee constructor:

super(firstname, gender);

Second, there's no need to call the Person constructor from the Dependent one. This will happen automatically when Dependent calls the Employee constructor, because the Employee constructor then calls the Person one.

score 0 · Answer 3 · edited May 23 '17 at 11:51

What you are looking for is something like the below, please note Classes start with Upper-case and camel case for method parameter staring with a lower-case letter. String must be upper-case String name , please also be aware you have introduced a protected member scope on name See the following post on the implications In Java, difference between default, public, protected, and private

  public abstract class Person
  {
    protected String name;

    public Person(String name)
    {
      if (name.length() <= 12)
      {
        this.name = name;
      }
      else
      {
        this.name = name.substring(0, 12);
      }
    }

    public final String returnName()
    {
      return name;
    }
  }

  public class Employee extends Person
  {
    private String gender = null;

    public Employee(String firstName, String gender)
    {
      super(firstName);
      this.gender = gender;
    }

  }

  public class Dependent extends Employee
  {
    private String relation = null;

    public Dependent(String firstName, String gender, String relation)
    {
      super(firstName, gender);
      this.relation = relation;
    }
  }

You will need to add methods to access the relation and gender if you need the access to these

Constructor two classes up java

3 Answers3