Isolate a term in a line

Question

I would like to isolate a term in a specific line defined as follow :

enO.u16LINK=0x01

I succeed in isolate 0x01 by using value=${lines##*=}. At the same time I succeed in retrieve enO.u16LINK using ${lines%=*}. However, I do not find how to isolate enO and u16LINK in two different variable.

Somebody knows a regular expression to satisfy this need ?

score 2 · Answer 1 · answered Nov 26 '14 at 23:57

2

Using a subshell:

$ read a b c <<< $(IFS=".="; set -- $line; IFS=" "; echo "$*")
$ echo $a
enO
$ echo $b
u16LINK
$ echo $c
0x01

answered Nov 26 '14 at 23:57

glenn jackman

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score 1 · Answer 2 · answered Nov 26 '14 at 23:24

1

Use cut ...

$ var1=`echo enO.u16LINK=0x01 | cut -d\= -f1 | cut -d\. -f1`
$ echo $var1
enO
$ var2=`echo enO.u16LINK=0x01 | cut -d\= -f1 | cut -d\. -f2`
$ echo $var2
u16LINK

answered Nov 26 '14 at 23:24

Red Cricket

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Thank Red. Just a last question. In your solution -f1 is associated to the first term, before -d\= and -d\., and -f2 to the second one, isn't it ? – ogs Nov 26 '14 at 23:53
read the man page. `man cut`:) – Red Cricket Nov 27 '14 at 02:15

score 1 · Accepted Answer · answered Nov 26 '14 at 23:25

1

Do the same thing you did already again.

$ lines=enO.u16LINK=0x01
$ value=${lines##*=}
$ key=${lines%=*}
$ key1=${key%.*}
$ key2=${key#*.}
$ echo value=$value
value=0x01
$ echo key=$key
key=enO.u16LINK
$ echo key1=$key1
key1=enO
$ echo key2=$key2
key2=u16LINK

answered Nov 26 '14 at 23:25

Etan Reisner

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Thank Etan ! Your solution is exactly that I searched. – ogs Nov 26 '14 at 23:51

Isolate a term in a line

3 Answers3