Bash Script, stdin

Question

I have a small problem here.

I've written a script, which works fine. But there is a small problem.

The script takes 1 or 2 arguments. The 2nd arguments is a .txt file.

If you write something like my_script arg1 test.txt, the script will work. But when you write my_script arg1 < test.txt it doesn't.

Here is a demo of my code:

#!/bin/bash

if [[ $# = 0 || $# > 2 ]]
then
    exit 1
elif [[ $# = 1 || $# = 2 ]]
then
    #do stuff

    if [ ! -z $2 ]
    then
        IN=$2
    else
        exit 3
    fi
fi

cat $IN

How can I make it work with my_script arg1 < test.txt?

What about parsing arguments, like this: http://stackoverflow.com/questions/192249/how-do-i-parse-command-line-arguments-in-bash — Danilo Muñoz, Nov 28 '14 at 19:28

score 2 · Accepted Answer · answered Nov 28 '14 at 19:48

If you just want to change how my_script is called, then just let cat read from myscript's standard input by giving it no argument:

#!/bin/bash

if [[ $# != 0 ]]
then
    exit 1
fi
cat

If you want your script to work with either myscript arg1 < test.txt or myscript arg1 test.txt, just check the number of arguments and act accordingly.

#!/bin/bash

case $# in
   0) exit 1 ;;
   1) cat ;;
   2) cat $2 ;;
esac

score 0 · Answer 2 · answered Nov 28 '14 at 21:09

0

If you look at how the guys at bashnative implemented their cat you should be able to use 'read' to get the piped content..

eg. do something like this:

   while read line; do
      echo -n "$line"
   done <"${1}"

HTH,

bovako

answered Nov 28 '14 at 21:09

Thijs Dalhuijsen

768
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14

Bash Script, stdin

2 Answers2