for x in range does not accept the last input

Question

new = 0
binary=input ("Enter binary:")
length = len(binary)
for x in range (0,3):
    if length<9 and all (c in "01" for c in binary):
        for digits in binary:
            new = new*2 + int(digits)
        print ("The binary numbers {0} converted into decimal is {1}".format(binary,new))
        break
    else:
        binary=input ("Try again. Enter binary (max. 8):")

print ("The programme will end")

The code works well and outputs the decimal format for the initial 3 inputs but for the last, when the input is correct it still outputs "The program will end" and not the decimals.

EDIT: Thanks for all the help, I've fixed the problem

You should read and understand the basics, the documentation makes it pretty clear how range works https://docs.python.org/2/library/functions.html#range — Padraic Cunningham, Dec 07 '14 at 00:02

score 4 · Answer 1 · answered Dec 06 '14 at 23:29

4

....for the initial 3 inputs but for the last

I see the following loop in your code

for x in range (0,3):

Note that the function range is "half-open" meaning it includes the first value, but not the last. In other words, x will take on the values

0
1
2

If you want to also include the value 3 you need

for x in range (0,4):

answered Dec 06 '14 at 23:29

Cory Kramer

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Thanks, is there any way I can have all values included? – Dec 06 '14 at 23:33
it's not clear. If you want the last value, then you can write lastvalue+1. For example you want to put values by user's, then you cant know what is the last number. So, if user's value=a, then you can write for x in range(0,a+1). – GLHF Dec 07 '14 at 00:40

for x in range does not accept the last input

1 Answers1