Lets say, I have a table:
+------------+-----------+------+-----+-------------------+-----------------------------+
| Field      | Type      | Null | Key | Default           | Extra                       |
+------------+-----------+------+-----+-------------------+-----------------------------+
| id         | int(10)   | NO   | PRI |                   | AUTOINCREMENT               |
| id_action  | int(10)   | NO   | IDX |                   |                             |
| a_date     | date      | NO   | IDX |                   |                             |
| a_datetime | datetime  | NO   | IDX |                   |                             |
+------------+-----------+------+-----+-------------------+-----------------------------+
Each row has some id_action, and the a_date and a_datetime when it was executed on the website.
My question is, when I want to return COUNT() of each id_action grouped by a_date, is it same, when I use this two selects, or they are different in speed? Thanks for any explanation.
SELECT COUNT(id_action), id_action, a_date
FROM my_table
GROUP BY a_date
ORDER BY a_date DESC
and
SELECT COUNT(id_action), id_action, DATE_FORMAT(a_datetime, '%Y-%m-%d') AS `a_date`
FROM my_table
GROUP BY DATE_FORMAT(a_datetime, '%Y-%m-%d')
ORDER BY a_date DESC
In other words, my question is, that each action has its datetime, and if I really need column a_date, or it is the same using DATE_FORMAT function and column a_datetime and I dont need column a_date?