array not store/print second part of name

Question

I am want to enter name in array and then willing to print it on screen. Code is given below

char name[20];          
cout << "Please enter name: ";
cin >> name;          
cout << name << endl;

Then after compilation I entered name

Ali Waqas

After that Ali is printed on screen but Waqas doesn’t. I have replace my cout statement with this loop

for(int i=0; i<20; i++){
   cout << name[i];
}

Again Ali is printed but after that garbage is printing rather Waqas

[`getline`](http://en.cppreference.com/w/cpp/string/basic_string/getline) — Borgleader, Dec 08 '14 at 15:47
So with `cin` and `cout`, obviously C++ code. You know C != C++, right? You should also be using `std::string` instead of C strings. — crashmstr, Dec 08 '14 at 15:47
@muhammadkhan _what about my question ?_ Check the 1st comment! Didn't need to be restated. — πάντα ῥεῖ, Dec 08 '14 at 15:53
This is possibly a duplicate of http://stackoverflow.com/questions/5838711/c-cin-input-with-spaces — Vamshi Krishna, Dec 08 '14 at 15:55

score 2 · Answer 1 · answered Dec 08 '14 at 15:47

2

This is because operator<< skips white space. You could use getline() to get the desired effect.

string str;
getline(cin, str);

answered Dec 08 '14 at 15:47

ravi

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thanks for suggestion, but for now i want to do it wit char array, rather string. – muhammad khan Dec 08 '14 at 15:51
1

@muhammadkhan Why?? Why would you use a cumbersome and unsafe array instead of the standard `std::string` type? – Angew is no longer proud of SO Dec 08 '14 at 15:54
@Angew i want to do experiment, as i am beginner of c/c++ – muhammad khan Dec 08 '14 at 16:26
@muhammadkhan Even more reason to learn & get familiar with the lanuage using everyday tools (`std::string`), before you delve down to the complex specialised ones (manual management of a nul-terminated `char` string). – Angew is no longer proud of SO Dec 09 '14 at 07:52

score 0 · Accepted Answer · answered Mar 28 '15 at 14:38

You should use

getline()

to get desired results. You will not get correct output with current code because operator << ignores the white spaces. You have to use this type of code

string str;
getline(cin, str);

For the further more details you must go through this link

array not store/print second part of name

2 Answers2