#include<stdio.h>
int main()
{
int a=5,b;
b=a++ + ++a ;
printf("%d",b);
return 0;
}
//now give a =5 when you scan for a instead of assigining a=5.
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4`b=a++ + ++a ;`...perfect example of well-defined `undefined behaviour`. – Sourav Ghosh Dec 12 '14 at 07:42
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I haven't got your answer can you tell me the reason for my question. just check the above code in codeblocks you will get different answer .when a is assigned a value and when a get the same value using scanf – ramesh Dec 12 '14 at 07:52
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there is no logic that can define something called undefined behavior. – Sourav Ghosh Dec 13 '14 at 13:38
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But I haven't got my answer . How can a same compiler can give two different answer when you are performing same task with same data. – ramesh Dec 14 '14 at 02:20