how to get rid off the error ArrayIndexOutOfBound Exception?

Question

public class Main {

public static void main(String[] args) {

    int[] numbers = {1, 2, 3}; // it gives me arrayindexoutofboundexception

    int length = numbers[3];

    char[] chars = new char[length];

    chars[numbers.length + 4] = 'y';

    System.out.println("Done!");
}

}

How to remove array index out of bound exception .

score 4 · Accepted Answer · answered Dec 23 '14 at 12:59

4

Don't access numbers[3]; when your array has only 3 elements, whose indices are 0, 1 and 2.

Also don't access chars[numbers.length + 4] before making sure this is a valid index of the chars array.

answered Dec 23 '14 at 12:59

Eran

387,369
54
702
768

Thanks a lot, it helped. what if i try to catch the exception,then it get compiled without exception but there is no output,can you explain,thanks? – Kedar Kholiya Dec 23 '14 at 13:09
@KedarKholiya Don't catch the exception. You should avoid it in the first place. – Eran Dec 23 '14 at 13:19

score 0 · Answer 2 · answered Dec 23 '14 at 13:01

0

Change:

int length = numbers[3];

To:

int length = numbers[2];

answered Dec 23 '14 at 13:01

StevenAkaTaz

70
7

done,but no help.giving runtime error – Kedar Kholiya Dec 23 '14 at 13:04
@KedarKholiya - Check *Eran's* answer. The line `chars[numbers.length + 4] = 'y';` is *suicidal*. – TheLostMind Dec 23 '14 at 13:04

how to get rid off the error ArrayIndexOutOfBound Exception?

2 Answers2