I need to find a way of reading in the last 6 lines of data from a file.
For example if I have 1 2 3 4 5 6 7 8 9 10
I need to read be able to get 10, 9, 8, 7, 6, 5, 4.
These need to then be put into variables or strings to be outputted later. Currently I have managed to read in the last line of the file but I have no idea how to then read in the other 5 numbers.
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
using namespace std; 
int main()
{
    std::ifstream in("test.txt");
    if (in.is_open())
    {
        std::vector<std::string> lines_in_reverse;
        std::string line, line2;
        while (std::getline(in, line))
        {
            // Store the lines in reverse order.
            lines_in_reverse.insert(lines_in_reverse.begin(), line);
        }
        cout << line << endl;
        while (std::getline(in, line2))
        {
            // Store the lines in reverse order.
            lines_in_reverse.insert(lines_in_reverse.begin(), line2);
        }
        cout << line2 << endl;
    }
    cin.get();
    return 0;
}
Can anyone advise a way to this? I do not know of any functions or methods that can help.
EDIT
This method outputs the last 6 numbers from the file however they are backwards and I need a way to reverse them and get rid of the whitespace it prints out.
I'm unsure on how to use reverse and which arguments are required from this - http://en.cppreference.com/w/cpp/algorithm/reverse
#include <iostream>
#include <fstream>
#include <string>
#include <algorithm>
using namespace std;
int main()
{
    char x;
    ifstream f("test.txt", ios::ate);
    streampos size = f.tellg();
    for (int var = 1; var <= size; var++){
        f.seekg(-var, ios::end);
        f.get(x);
        reverse(x);
        cout << x; 
    }
    cin.get();
    return 0;
}
Alot of the responses show me how to reverse the text file using vectors but not the last 6 numbers which is the only information I need.
Regards