I am trying to implement a thread safe STL vector without mutexes. So I followed through this post and implemented a wrapper for the atomic primitives.
However when I ran the code below, it displayed out Failed!twice from the below code (only two instances of race conditions) so it doesn't seem to be thread safe. I'm wondering how can I fix that?
Wrapper Class
template<typename T>
struct AtomicVariable
{
std::atomic<T> atomic;
AtomicVariable() : atomic(T()) {}
explicit AtomicVariable(T const& v) : atomic(v) {}
explicit AtomicVariable(std::atomic<T> const& a) : atomic(a.load()) {}
AtomicVariable(AtomicVariable const&other) :
atomic(other.atomic.load()) {}
inline AtomicVariable& operator=(AtomicVariable const &rhs) {
atomic.store(rhs.atomic.load());
return *this;
}
inline AtomicVariable& operator+=(AtomicVariable const &rhs) {
atomic.store(rhs.atomic.load() + atomic.load());
return *this;
}
inline bool operator!=(AtomicVariable const &rhs) {
return !(atomic.load() == rhs.atomic.load());
}
};
typedef AtomicVariable<int> AtomicInt;
Functions and Testing
// Vector of 100 elements.
vector<AtomicInt> common(100, AtomicInt(0));
void add10(vector<AtomicInt> ¶m){
for (vector<AtomicInt>::iterator it = param.begin();
it != param.end(); ++it){
*it += AtomicInt(10);
}
}
void add100(vector<AtomicInt> ¶m){
for (vector<AtomicInt>::iterator it = param.begin();
it != param.end(); ++it){
*it += AtomicInt(100);
}
}
void doParallelProcessing(){
// Create threads
std::thread t1(add10, std::ref(common));
std::thread t2(add100, std::ref(common));
// Join 'em
t1.join();
t2.join();
// Print vector again
for (vector<AtomicInt>::iterator it = common.begin();
it != common.end(); ++it){
if (*it != AtomicInt(110)){
cout << "Failed!" << endl;
}
}
}
int main(int argc, char *argv[]) {
// Just for testing purposes
for (int i = 0; i < 100000; i++){
// Reset vector
common.clear();
common.resize(100, AtomicInt(0));
doParallelProcessing();
}
}
Is there such a thing as an atomic container? I've also tested this with a regular vector<int> it didn't have any Failed output but that might just be a coincidence.