How to access keydown via function?

Question

I need to make sure input on dynamically generated input fields accept only numbers.

This jsfiddle is doing exactly what I want but it isn't allowing for dynamically generated fields: http://jsfiddle.net/lesson8/HkEuf/1/.

I've modified it to work with a function but it isn't doing anything. Any ideas what I'm doing wrong?

HTML:

Number : <input onkeydown="test(this);" type="text" name="quantity" id="quantity" />&nbsp;<span id="errmsg"></span>

Javascript:

function test(input) {
  //called when key is pressed in textbox
  input.keypress(function (e) {
     //if the letter is not digit then display error and don't type anything
     if (e.which != 8 && e.which != 0 && (e.which < 48 || e.which > 57)) {
        //display error message
        $("#errmsg").html("Digits Only").show().fadeOut("slow");
               return false;
    }
   });
}

CSS:

#errmsg
{
color: red;
}

Function version: http://jsfiddle.net/HkEuf/4776/

you're fiddle was being weird. also you forgot to wrap `input` in a `$`. See here: http://jsfiddle.net/HkEuf/4777/ — chiliNUT, Jan 10 '15 at 00:24

score 0 · Answer 1 · answered Jan 10 '15 at 00:20

0

You should use .delegate.

 $('#container', 'input', 'keypress', function() {
     // your code here
 });

answered Jan 10 '15 at 00:20

Daniel A. White

187,200
47
362
445

it can be body or some wrapping element - its so that you don't apply it to everything. – Daniel A. White Jan 10 '15 at 00:21

score 0 · Answer 2 · answered Jan 10 '15 at 00:24

Try this:

<input value="" onkeypress="return onlyNumber(event)" />

<script type="text/javascript">

function onlyNumber(e) {
    e = (e) ? e : window.event;
    var charCode = (e.which) ? e.which : e.keyCode;
    if (charCode > 31 && (charCode < 48 || charCode > 57)) {
        return false;
    }
    return true;
}

</script>

How to access keydown via function?

2 Answers2