What is execution order of overriding in Java?

Question

Parent instance = new Child();
instance.method();

When we call method, JVM will find child method directly or find parent class firstly, find child, find method, or some other sequence?

possible duplicate of [When do you use Java's @Override annotation and why?](http://stackoverflow.com/questions/94361/when-do-you-use-javas-override-annotation-and-why) — Shantha Kumara, Jan 16 '15 at 04:12
@ShanthaKumara It seems no answers. Could you just tell me whether the JVM will find the method in subclass directly depend on the actual implemented class? — cow12331, Jan 16 '15 at 04:23
The `method()` is first searched in the Child then Parent. In other words, JVM starts from most specific implementation to generic implementation to find the `method()`. — Shantha Kumara, Jan 16 '15 at 04:54

score 0 · Answer 1 · answered Sep 14 '21 at 10:26

If I may add a more comprehensive example:

class Parent {
    public void print() {
        System.out.println("Hello from Parent");
    }
}

class Child extends Parent {
    @Override
    public void print() {
        System.out.println("Hello from Child");
    }
}

public class Main {
    public static void main(String[] args) { 
        Parent parent = new Child();
        parent.print();
    }
}

This program will print Hello from Child. Although we instantiate the Child via the Parent, Java will look for the "nearest" implementation of print(), starting from the child.

What is execution order of overriding in Java?

1 Answers1