Hi I have a problem calculating the area of a polygon in Bing maps. I'm using this code to calculate area.
public static double PolygonArea(LocationCollection points, double resolution)
    {
        int n = points.Count;
        var partialSum = 0.0;
        var sum = 0.0;
        for (int i = 0; i < n - 1; i++)
        {
            partialSum = (points[i].Longitude * points[i + 1].Latitude) -
                (points[i + 1].Longitude * points[i].Latitude);
            sum += partialSum;
        }
        var area = 0.5 * sum / Math.Pow(resolution, 2);
        area = Math.Abs(area);
        return area;
    }
This is the resolution method
public static double Resolution(double latitude, double zoomLevel)
  {                
      double groundResolution = Math.Cos(latitude * Math.PI / 180) *
       2 * Math.PI * EARTH_RADIUS_METERS / (256 * Math.Pow(2, zoomLevel));
            return groundResolution;
   }
How can I trasform it in m^2?
EDIT1: I tried your answer but I noticed that area change if I change zoom level.
I try to explain my problem from another point of you. I have to make the porting of an iOS app that uses this algorithm to calculate area
-(long double)calcArea :(CLLocationCoordinate2D*) pastureCordinates :(long) count {
  long double area  = 0.0;
  long double scale = 0.0;
  for (int cnt = 1; cnt < count; cnt++) {
      area +=    (MKMapPointForCoordinate(pastureCordinates[cnt - 1]).x)
      * (MKMapPointForCoordinate(pastureCordinates[cnt]).y)
      - (MKMapPointForCoordinate(pastureCordinates[cnt]).x)
      * (MKMapPointForCoordinate(pastureCordinates[cnt - 1]).y);
  }
  area +=    (MKMapPointForCoordinate(pastureCordinates[count - 1]).x)
  * (MKMapPointForCoordinate(pastureCordinates[0]).y)
  - (MKMapPointForCoordinate(pastureCordinates[0]).x)
  * (MKMapPointForCoordinate(pastureCordinates[count - 1]).y);
  scale = MKMapPointsPerMeterAtLatitude(pastureCordinates[count -1].latitude);
  area  = (area / (long double)2) / pow(scale,2);
  area = fabsl(area);
  return area;
}
I used the functions found here: https://msdn.microsoft.com/en-us/library/bb259689.aspx to calculate the scale, the ground resolution but the results are different compared to the iOS solution.