Check if an expression is an lvalue with the preprocessor

Question

Is there a macro which checks if an expression is a lvalue (meaning I can do &expression) using the C preprocessor?

Example: If there is some int a; and I call IS_LVALUE(a) it should evaluate to 1, while IS_LVALUE(5) should evaluate to 0, so I can do #if IS_LVALUE(...) == 1

I'm trying to create lamba expressions using preprocessor macros. When passing an argument, I need to know if it's an lvalue (Then I create a pointer) or not (then I just pass the value). See http://stackoverflow.com/a/28332447/773690 — iblue, Feb 04 '15 at 22:10

Quentin · Accepted Answer · 2015-02-04T22:17:18.853

11

No.

Because the C preprocessor has no clue what an lvalue is, or any other C construct for that matter. That's the compiler's job.

Were you in C++ you could use a type trait, but in C I'm afraid you're out of luck.

edited Feb 04 '15 at 22:17

answered Feb 04 '15 at 21:55

Quentin

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Check if an expression is an lvalue with the preprocessor

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