Run compiled python .exe with a file as input

Question

So I made a program in Python and compiled it to .exe. This works fine. What I want is to be able to double click files I created (say with text in them) and open those files with the .exe I compiled and then do something with the files as input.

I figured one way to do this might be to at least get the exact location of the file that is being opened with the .exe so as a first test something like this:

.exe file:

get_location = dirname(realpath(My_Clicked_File))
print get_location

The file clicked will be some random extension so .test or something I made up.

I haven't tried it, but I expect if you make your .exe the default opening program for a particular file type, and double click a file of that type, then its name and path will be available in `sys.argv`. — Kevin, Feb 06 '15 at 13:16
possible duplicate of [Create registry entry to associate file extension with application in C++](http://stackoverflow.com/questions/1387769/create-registry-entry-to-associate-file-extension-with-application-in-c) — ivan_pozdeev, Feb 06 '15 at 13:20
I will look into the other post and return if that helped me. Thanks (I couldn't have found that file with my knowledge on what to search :D) — Wealot, Feb 06 '15 at 13:23

score 1 · Accepted Answer · answered Feb 06 '15 at 13:18

1

If you've associated your file extension with your exe, when you double-click on the file its full file path will be passed as the first argument, which you can get from sys.argv in your script.

answered Feb 06 '15 at 13:18

Daniel Roseman

588,541
66
880
895

That actually gives the path of the .exe and not the file doubleclicked (tried that first). – Wealot Feb 06 '15 at 13:23
2

Did you check the second argument? – Matthias Feb 06 '15 at 13:38
On second thought Yes this is the answer. It just is not the first argument from sys.argv[0] but it is the second so sys.argv[1]. Thanks! – Wealot Feb 06 '15 at 13:41

Run compiled python .exe with a file as input

1 Answers1