PHP substitute, "If $something = "0" then $something1 = "no""

Question

So basically what am trying to achieve is the following.

I am trying to make it so the following script does something in this instance:

If $something == "0" then $something1 == "no"
If $something == "1" then $something1 == "yes"
else echo "Error."

That is how I would explain what Im trying to do.

This is my current code:

<?php
if(isset($_POST['resolve'])){
    $api = "http://test.com/php/";
    if(strlen($_POST['name'])==0){
        echo "fill in all fields!";
    } else {
        $response = file_get_contents($api.$_POST['name']); 
        $array = unserialize($response);
        ?>
        <div align="center"><?php echo "".$array['something1']; ?></div>
        <?php
     }
}
?>

I would like it to echo "no" if the result of array "something" is "0" and echo "yes" if the result of array "something" is "1".

Try [`else if`](http://php.net/manual/control-structures.elseif.php)? — A.L, Feb 14 '15 at 13:06

k32y · Answer 1 · 2015-02-14T13:16:00.373

1

<?php
if($array['something'] == '0'){echo 'No';}
elseif($array['something'] == '1'){ echo 'Yes';}
else{ echo 'Error!'; }
?>

edited Feb 14 '15 at 13:16

answered Feb 14 '15 at 13:10

k32y

407
6
11

score 1 · Answer 2 · answered Feb 14 '15 at 13:59

1

switch case is the most elegant way to go here:

switch($array['something']) {
    case 0: echo 'No';break;
    case 1: echo 'Yes';break;
    default: echo 'Error.';
}

answered Feb 14 '15 at 13:59

vcanales

1,818
16
20

Paul · Accepted Answer · 2015-02-14T13:37:05.207

<?php
if(isset($_POST['resolve'])) {
    $api = "http://test.com/php/";
    if(!$_POST['name']) {
        echo "Please, fill in all fields!";
    } else {
        $response = file_get_contents($api.$_POST['name']); 
        $array = unserialize($response);
        echo "<div align='center'>";
            if($array['something'] == '0') {
                echo 'No';
            }
            elseif($array['something'] == '1') {
                echo 'Yes';
            }
            else {
                echo 'Error.';
            }
        echo "</div>";
    }
}
?>

Don't forget to also do a security input check on $_POST['name']

What do you mean security input? – user3724476 Feb 14 '15 at 13:49 — user3724476, Feb 14 '15 at 13:49

score 0 · Answer 4 · answered Feb 14 '15 at 13:51

0

Voila

echo $array['something1'] ? "Yes" : "No";

answered Feb 14 '15 at 13:51

Adam

17,838
32
54

1

This would echo Yes for any `value >= 1`. – vcanales Feb 14 '15 at 14:00

score 0 · Answer 5 · answered Feb 14 '15 at 14:11

This sets $array['something1'] to either 'yes' or 'no' depending on the value of $array['something'].

<?php
if(isset($_POST['resolve'])){
    $api = "http://test.com/php/";
    if(strlen($_POST['name'])==0){
        echo "fill in all fields!";
    } else {
        $response = file_get_contents($api.$_POST['name']); 
        $array = unserialize($response);
        $array['something1'] = $array['something'] == 0 ? 'no' : 'yes';
        ?>
        <div align="center"><?php echo "".$array['something1']; ?></div>
        <?php
     }
}

score 0 · Answer 6 · answered Feb 14 '15 at 15:17

0

$yesno = ['No', 'Yes'];
$something1 = $yesno[$something];

That is the simplest way I know of doing it.

answered Feb 14 '15 at 15:17

vascowhite

18,120
9
61
77

PHP substitute, "If $something = "0" then $something1 = "no""

6 Answers6