Get value from php function to javascript

Question

I am stuck with getting an array from php function located in another file to a javascript. I used the below code but nothing is happening.

PHP code:

$sprd_array;
$spread = 0;
    foreach ($data as $key => $value) {
        $spread =(int) ($value->ask*100000) - ($value->bid * 100000);
        $spread =(float) $spread / 10000;
        $spread = round( $spread, 5, PHP_ROUND_HALF_UP);
        $sprd_array[] = $spread;
    }
    for($i = 0;$i < sizeof($sprd_array); $i++){
        //echo "spread: " . $sprd_array[$i] . "<br />";
    }
    return $sprd_array;
}

I want to get the array in another javascript file.

javascript code:

$.ajax({
    url:'jsondecode.php',
    complete: function (response) {
        alert("done");
    },
    error: function () {
        alert("error");
    }
});
return false;

Your PHP code has **OUTPUT** your value. a `return` doesn't output anything. `echo json_encode($sprd_array)` would do the trick. echoing out the array directly would just produce the literal word `Array`. — Marc B, Feb 19 '15 at 15:52
would you please explain with a code. I didn't understand you very well sorry — Kevin k5, Feb 19 '15 at 15:56
possible duplicate of [How to pass variables and data from PHP to JavaScript?](http://stackoverflow.com/questions/23740548/how-to-pass-variables-and-data-from-php-to-javascript) — Jon Surrell, Feb 19 '15 at 16:00

score 0 · Answer 1 · answered Feb 19 '15 at 15:50

0

Do it like

$.ajax({
      url:'jsondecode.php',
      dataType : json,
      success: function (data) {
         console.log(data); // This is the data you want.
      },
      error: function () {
          alert("error");
      }
  });

answered Feb 19 '15 at 15:50

void

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nothing happened. should I add any code in the php file ? like if($_POST...etc ?? I put alert on success and error and am not getting any message – Kevin k5 Feb 19 '15 at 15:53
Have you included jquery file? – void Feb 19 '15 at 15:55
You Need to include the jquery source file; you can download it here : http://jquery.com/download/ – Tacticus Feb 19 '15 at 16:12
Use the code before doing this ajax, `` – void Feb 19 '15 at 17:02

score 0 · Answer 2 · answered Feb 19 '15 at 15:52

In PHP, use the function json_encode() to encode your objects / arrays to JSON Format. Note that setting the second argument to true will keep associative array indeces.

Also, your JavaScript code is not alright. You need to use success: instead of complete:. Then, you can easily convert the string back into an object using JSON.parse(yourJSONString);.

n-dru · Answer 3 · 2015-02-19T16:30:30.283

0

In php change "return $sprd_array;" to:

echo json_encode($sprd_array);

edited Feb 19 '15 at 16:30

answered Feb 19 '15 at 15:55

n-dru

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I did it but the alert is not showing. It means its stuck in a place I can't find. – Kevin k5 Feb 19 '15 at 15:59
There is no such function is JavaScript. You need to use `JSON.parse(jsonString)` as described in my answer. – Tacticus Feb 19 '15 at 16:07
should I include a JQuery file ? – Kevin k5 Feb 19 '15 at 16:10
@Tacticus I forgot - json_decode is just function in js that I defined and always use, of course it should do what you described, sorry. – n-dru Feb 19 '15 at 16:20
@Tacticus using JSON.parse didn't solve the problem. nothing is happening. – Kevin k5 Feb 19 '15 at 16:28
make sure you echo in php, and not return, if it is ajax! – n-dru Feb 19 '15 at 16:29

Get value from php function to javascript

3 Answers3