python execute list and list of functions

Question

I'm utilizing Python 2.7 with Autodesk Maya. Here's an example of my issue:

import maya.cmds as m

def a(passedString):
    print('this'+passedString)
def b(passedString):
    print('that'+passedString)
def c(passedString):
    print('notThis'+passedString)
def d(passedString):
    print('ofCourse'+passedString)
string1 = [a(),b(),c(),d()]
string2 = [poly1,poly2,poly3,poly4]
for each in string2 and every in string1:
    m.select(each)
    every(each)

This might seem straight forward, but what I need is to have string2[0] (a function) executed with string1[0] and only string1[0].

Same goes for the next array item. [1] with [1] and [2] with [2] and [3] with [3].

Essentially, I'm trying to cut down on code and simplify how my code executes, as opposed to tediously writing the above code for 20+ individual instances.

You probably want to do: `string1 = [a,b,c,d]` – Nir Alfasi Feb 20 '15 at 17:48 — Nir Alfasi, Feb 20 '15 at 17:48

Cory Kramer · Accepted Answer · 2015-02-20T18:01:59.320

You can zip the lists to iterate through them in an element-wise fashion

for func, param in zip(string1, string2):
    func(param)

For example

string1 = [len, type, max]
string2 = ['hello', 5, [1,3,7]]
for func, param in zip(string1, string2):
    func(param)

Output

5
<class 'int'>
7

Also note that in your list of functions you should not add () to the end of the function because you will call the function if you do so. Just leave the function name itself (see the above string1 list for example).

For your code the loop would look like

for each, every in zip(string2, string1):
    m.select(each)
    every(each)

python execute list and list of functions

1 Answers1

Linked