Nothing happens with this code. Why?

Question

public void main(String[] args) {
    System.out.println("Hello World!");
}

This compiles in my environment, but nothing happens at run time.

Please show the full class, and how you're executing it. If that's all there is, I'd expect an exception due to the VM not finding a *static* `main` method to launch. — Jon Skeet, Feb 26 '15 at 09:59
Please Look at the accepted answer of this link. http://stackoverflow.com/questions/146576/why-is-the-java-main-method-static — Vivek Mishra, Feb 26 '15 at 10:02
Thanks all for the quick replies. This solved my problem. What a pesky little error. — , Feb 26 '15 at 10:15

score 3 · Answer 1 · answered Feb 26 '15 at 09:58

3

If should be a static method, otherwise it can't serve as the entry point of a Java application.

public static void main(String[] args) 
       ------
{
    System.out.println("Hello World!"); 
}

answered Feb 26 '15 at 09:58

Eran

score 3 · Answer 2 · answered Feb 26 '15 at 09:59

3

The main method should be : public static void main(String[] args)

answered Feb 26 '15 at 09:59

TheLostMind

`public`, `static` and `void` are not part of the signature :) – Konstantin Yovkov Feb 26 '15 at 10:00

score 1 · Answer 3 · edited Feb 26 '15 at 10:07

1

public void main(String[] args)

change this to

public static void main(String[] args)

edited Feb 26 '15 at 10:07

Pang

answered Feb 26 '15 at 09:59

V__

atish shimpi · Answer 4 · 2015-02-26T10:05:14.593

1

main() method syntax is,

public static void main(String[] args)

you are missing static, so JVM not able to find your main() method i.e. entry point so there is noting happened.

Check your console It should display error message as

java.lang.NoSuchMethodError: main
Exception in thread "main"

edited Feb 26 '15 at 10:05

answered Feb 26 '15 at 09:59

atish shimpi

4 Answers4