error when Parsing input c

Question

Hi i am writing a simple c program to test parsing a buffer in c but when i run the program i get the following errors:

./test.c: line 4: syntax error near unexpected token `('
./test.c: line 4: `int main()'

Does anyone know why these errors are occurring? Thanks

#include <stdio.h>
#include <stdlib.h>

int main()
{

    char* command;

    char* buf = malloc(100 *sizeof(char));

    buf = "GET /index.html HTTP/1.1\n Host: www.gla.ac.uk\n";

    command  = strtok(buf, " ");
    printf("%s", command );

    free(buf);
}

score 6 · Accepted Answer · answered Mar 04 '15 at 09:30

6

I think you are trying to run source code without compiling. That's not the proper way to do.
First compile the source code

gcc test.c -o test

Then execute it

./test

answered Mar 04 '15 at 09:30

niyasc

4,440
1
23
50

1

Good spot. Just tried it in bash and I get the exact error reported in the question. – JeremyP Mar 04 '15 at 09:49

score 1 · Answer 2 · answered Mar 04 '15 at 09:27

1

After

buf = "GET /index.html HTTP/1.1\n Host: www.gla.ac.uk\n";

do not

free(buf);

I suppose you should do

strncpy(buf, "GET /index.html HTTP/1.1\n Host: www.gla.ac.uk\n", 100);

instead of

buf = "GET /index.html HTTP/1.1\n Host: www.gla.ac.uk\n";

And correct mallocing looks like:

char* buf = (char *)malloc(100 *sizeof(char));

answered Mar 04 '15 at 09:27

VolAnd

6,367
3
25
43

No, [don't cast the result of malloc](http://stackoverflow.com/a/605858/1606345) in C – David Ranieri Mar 04 '15 at 09:53

score 0 · Answer 3 · answered Mar 04 '15 at 09:35

0

You actually want a copy of your string, as the string literal you'd like to assign is constant. You can use strdup, or probably safer, use strndup to make a copy of the string. This does implicitly use malloc, so you should free it afterwards.

answered Mar 04 '15 at 09:35

Jan

293
1
11

error when Parsing input c

3 Answers3