How could I write expression like map (-3) [1..10] in haskell?

Question

It seems that (-3) is treated as a negative number instead of a curried function in haskell.

if I write

map (+3) [1..3]

I get [4,5,6]

However, map (-3) [1..3] would cause an error.

So, How could I map (-) to a list elegantly instead of having to use map (\x->x-3) xs?

map (subtract 3) [1..10] – TheCriticalImperitive Mar 05 '15 at 01:39 — TheCriticalImperitive, Mar 05 '15 at 01:39

score 0 · Answer 1 · answered Mar 05 '15 at 02:07

0

You can try:

map (flip (-) 3) [1..3]

-- or the other way around
map (3 -) [1..3]

answered Mar 05 '15 at 02:07

Alexandr Kurilin

score 0 · Answer 2 · answered Mar 05 '15 at 02:17

0

You could also do something like this:

map (-3 +) [1..3]

answered Mar 05 '15 at 02:17

2 Answers2