Incremental command in bash script

Question

I have a bash script that I use to call a c++ program, each time indicating a different file name (see below). At present the file number is not increasing; do you have any suggestion on how to change that? Thanks!

for i in {0..48}; do
    ./program file$05i.jpeg
done

Maybe you should update your question with the description of what you want. — PatJ, Mar 12 '15 at 02:30

score 4 · Accepted Answer · edited May 23 '17 at 11:43

4

Seems like you mean this,

for i in {0..48}; do
    ./program file05$i.jpeg
done

This will execute file050.jpeg, file051.jpeg upto 48.

Update:

for i in $(seq -f "%05g" 0 48); do
    ./program file$i.jpeg
done

Reference

edited May 23 '17 at 11:43

Community

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answered Mar 12 '15 at 02:18

Avinash Raj

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Hi Avinash, the files I need to execute are named `file00001.jpeg`, `file00002.jpeg` up to `file00048.jpeg` – albus_c Mar 12 '15 at 02:24
Thanks that works! What if the filename is like `file00001_000.jpeg`? – albus_c Mar 12 '15 at 02:46
1

`./program file$i*.jpeg` – Avinash Raj Mar 12 '15 at 02:47

Incremental command in bash script

1 Answers1