get App working directory - JAVA

Asked Mar 14 '15 at 17:56

Active Mar 14 '15 at 17:56

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I'm Making my first step going from C# to JAVA and have plenty of stuff that I dont get .. :( I was searching for a way to get current directory in JAVA

and found this answer(one of many one ) :

String path = new File(".").getCanonicalPath();

my question is : what is the role of File(".") + what is going under the hood ?

I got used to Directory.GetCurrentDirectory(); and never asked my self how is it working

edited May 23 '17 at 12:28

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asked Mar 14 '15 at 17:56

LordTitiKaka

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It looks like an attempt to get a path to the user's directory. Something I usually do `System.getProperty("user.dir")` for. – Hovercraft Full Of Eels Mar 14 '15 at 17:58
`"."` is simply the path to the current directory, that's all. – Hovercraft Full Of Eels Mar 14 '15 at 23:53
@HovercraftFullOfEels can you please explain ? , this is "." like you see in Linux ? – LordTitiKaka Mar 15 '15 at 08:11

get App working directory - JAVA

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