Can I avoid device qualifier when calling a function on the GPU?

Question

Functions that will be run on the GPU need the qualifier __device__. I'm currently writing a general set of mathematical functions, which can be used on the GPU as well as on the CPU. I think it's not very nice to qualify all those functions as __device__ since they might also be included into other programs where no CUDA is present at all. Is there a way to leave out the __device__?

score 2 · Answer 1 · answered Mar 22 '15 at 19:16

2

You can just compile with -D__device__="" when building for a non-CUDA target, or perhaps use a more general-purpose macro which can be defined as __device__ when compiling for CUDA.

answered Mar 22 '15 at 19:16

Paul R

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score 1 · Answer 2 · answered Mar 22 '15 at 19:28

1

#ifndef __CUDACC__
#define __device__
#endif

Or similar. Of course, you would need similar guards to deal with includes and functions that don't make sense in a non-CUDA setting.

answered Mar 22 '15 at 19:28

Can I avoid __device__ qualifier when calling a function on the GPU?

2 Answers2

Can I avoid device qualifier when calling a function on the GPU?