How to run gulp tasks sequentially?

Question

I have a few tasks in gulp and all of them except one could be run in parallel. Let's consider an example:

var gulp = require('gulp');
gulp.task('clean', function() {
    // clean up output folder
});
gulp.task('copy1', function() {
    // writes stream in the output folder
});
gulp.task('copy2', function() {
    // writes stream in the output folder
});

gulp.task('default', ['clean', 'copy1', 'copy2']);

In this example I need to run copy1 and copy2 in parallel but only after clean. How can I do this trick?

Answer 1

var runSequence = require('run-sequence');
gulp.task('default', function(callback) {
    runSequence('clean', ['copy1', 'copy2'], callback);
});

Answer 2

Be careful - there is a bug in gulp 3.x where even when using runSequence, the stream will return premature when file i/o is involved. Check out this post if you have issues: