PHP How to pass checkbox states after POST

Question

I have a quick question but I seem to be having trouble locating the answer. (possibly my wording) but here goes.

I was able to echo POST data from a form for the text/number variables without a hitch! but I am running in to a brick wall over these checkbox values.
I know that if you POST a checkbox it will post a value of "on" but lets say on the form if checkbox1 is checked, how to I make a corresponding checkbox on the POST page load already checked?
I know in html all you have to do is simply write "checked" within the code so I tried using an if statement to get the job done but I couldn't seem to get it working.

Any help is much appreciated!

Thanks!

I think it is `checked="checked"`. Can you post the code you've tried? — chris85, Apr 01 '15 at 05:29

Sagar Naliyapara · Accepted Answer · 2015-06-23T11:53:59.113

2

HTML:

<input type='checkbox' name='selected' value='1'>

PHP:

$selected = isset($_POST['selected']) && $_POST['selected']  ? "1" : "0";

This code will set selected checkbox with value 1 in variable $selected and 0 if not selected.

edited Jun 23 '15 at 11:53

answered Apr 01 '15 at 05:29

Sagar Naliyapara

score 0 · Answer 2 · answered Apr 01 '15 at 05:27

0

check box name will be available in post only if it is checked.

answered Apr 01 '15 at 05:27

vinay rajan

score 0 · Answer 3 · edited May 23 '17 at 12:22

0

        if (isset($_POST['myCheckbox'])) {
          $checkBoxValue = "yes";
        } else {
        $checkBoxValue = "no";
        }

edited May 23 '17 at 12:22

Community

answered Apr 01 '15 at 05:29

kailash sharma

3 Answers3