Inconsistent accessibility: Base class is less accessible than subclass

Question

I'm trying to create an object of RecipeManager in mainForm but I get this error:

Inconsistent accessibility: base class 'Assign_1.ListManager<Assign_1.Recipe>' is less accessible than class 'Assign_1.Managers.RecipeManager'

RecipeManager:

public class RecipeManager : ListManager<Recipe>
    {
        public RecipeManager()
        {

        }
    }

ListManager:

 public class ListManager<T> : IListManager<T>
    {
        protected List<T> m_list;

        public ListManager()
        {
            m_list = new List<T>();
        }

        public int Count
        {
            get { return m_list.Count; }
        }

I have another manager class that works fine:

public class AnimalManager : ListManager<Animal>
{
    private int startID =100;

    public AnimalManager()
    {
    }

I have all Manager classes in a folder called Managers

Are you sure they all have `public` before the class declaration like you've posted here? — Cameron, Apr 07 '15 at 21:48
Check accessibility of the interface - should be also public — eXavier, Apr 07 '15 at 21:50
@FilipHurta Huh? Interfaces don't need to be public, do they? It's normal for a public class to implement an internal interface. — , Apr 07 '15 at 21:54

score 10 · Accepted Answer · edited May 23 '17 at 12:13

10

Generic class is as accessible as least accessible of all parameter. So most likely Recipe class is not public.

Fix: make sure to declare Recipe as public explicitly.

Note that omitting accessibility is most likely reason of class not being public - check out What are the Default Access Modifiers in C#? for defaults.

class Recipe { ... {

means

internal class Recipe {....}

edited May 23 '17 at 12:13

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answered Apr 07 '15 at 21:53

Alexei Levenkov

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Inconsistent accessibility: Base class is less accessible than subclass

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