Splitting a list within a list in python

Question

How can I make a function to return the lowest number in a list like:

listA = [[10,20,30],[40,50,60],[70,80,90]]

I want it to return 10

possible duplicate of [Flattening a shallow list in Python](http://stackoverflow.com/questions/406121/flattening-a-shallow-list-in-python) — whereswalden, Apr 12 '15 at 03:04

score 2 · Answer 1 · answered Apr 12 '15 at 05:36

2

Flatten the list by using itertools.chain, then find the minimum as you would otherwise:

from itertools import chain

listA = [[10,20,30],[40,50,60],[70,80,90]]
min(chain.from_iterable(listA))
# 10

answered Apr 12 '15 at 05:36

nelfin

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score 1 · Answer 2 · answered Apr 12 '15 at 05:40

1

>>> listA = [[10,20,30],[40,50,60],[70,80,90]]
>>> min(y for x in listA for y in x)
10

answered Apr 12 '15 at 05:40

jamylak

128,818
30
231
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score 0 · Answer 3 · answered Apr 12 '15 at 02:41

0

Set result to float("inf"). Iterate over every number in every list and call each number i. If i is less than result, result = i. Once you're done, result will contain the lowest value.

answered Apr 12 '15 at 02:41

Schilcote

2,344
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This is one way to do it, but not the python way. – Snakes and Coffee Apr 12 '15 at 08:21

score 0 · Answer 4 · answered Apr 12 '15 at 16:56

0

This is possible using list comprehension

>>> listA = [[10,20,30],[40,50,60],[70,80,90]]
>>> output = [y for x in listA for y in x]
>>> min(output)
10

answered Apr 12 '15 at 16:56

bhawani shanker

79
3

Splitting a list within a list in python

4 Answers4