python: IndexError: list index out of range (file = sys.argv[1])

Question

if __name__ == "__main__":
    file = sys.argv[1]
    f = FST("q0")
    #f.addState("1", True)
    #f.addState("2", True)
    #f.addState("3", True)

in line file = sys.argv[1] getting this error. can anyone please help me out.

So what arguments are you giving your script? – Martijn Pieters Apr 14 '15 at 17:04 — Martijn Pieters, Apr 14 '15 at 17:04

score 1 · Answer 1 · answered Apr 14 '15 at 17:05

The sys.argv list is populated only when command line arguments to the script are present. sys.argv[0] is the name of the script you are running. sys.argv[1] will be the first command line argument passed to the script. You need to call your script like:

python SCRIPT_NAME FIRST_ARG

score 0 · Answer 2 · answered Apr 14 '15 at 16:59

You're probably running your script without arguments while it expects at least one.

sys.argv is the list of arguments given to the script. sys.argv[0] is the script itself; sys.argv[1] is the first actual argument. If you give no argument to the script, 1 is an out of range index.

python: IndexError: list index out of range (file = sys.argv[1])

2 Answers2