Random number isn't within contraints

Question

So, I did re did the e=(high-low)*x+low, however, when I try to use it, it just returns an outOfBounds exception. When I didn't cast it into an int, it worked, however I ned it to return an integer, for the array to work.

public static int randomInt(int low, int high)
    {double e;
    double x=Math.random();
        e=(high-low)*x+low;
    return (int)e;}

Here is the method that calls the "randomInt" method

public static int[] randomIntArray(int n)//generates an array of random numbers based on an upper and lower bound
    {int[] a=new int[n];
    for(int i=0;i<a.length;i++)
        {a[i]=randomInt(-5,15);}//"-5&15 are the lower and upper bounds of the random number array
    return a;}

Answer 1

x is between 0 and 1.

In order for e to be between low and high, you need:

e=(high-low)*x+low;

Answer 2

Check this

public static int randInt(int min, int max) {

    Random rand = new Random();

    // nextInt is normally exclusive of the top value,
    // so add 1 to make it inclusive
    int randomNum = rand.nextInt((max - min) + 1) + min;

    return randomNum;
}

Answer 3

Use return (int) (Math.random()*(high-low)+low); as your function body instead.