Printing multiple outputs on same line

Question

there. I'm self learning C++ out of "C++ without fear". There is an exercise dealing with the GCD of 2 numbers that asks to print "GCD(a,b) =>" at each step in the proceedure. I was able to get this working:

int gcd (int a, int b);

int main() {
    int i,j;
    cout << "Enter the first integer" << endl;
    cin >> i;
    cout << "Enter the second integer" << endl;
    cin >> j;
    int k = gcd(i,j);
    cout << "The GCD is " << k << endl; 
    system("PAUSE");
    return 0;
}

int gcd (int a, int b){
    if(b==0){
        cout << "GCF(" << a;
        cout << "," << b;
        cout << ") => " <<endl;
        return a;
    }
    else {
        cout << "GCF(" << a;
        cout << "," << b;
        cout << ") => " << endl;
        return gcd(b,a%b);
    }
}

I was just wondering if there is a nicer way to go about printing each step of finding the GCD. That is, is there a "nicer" way to write this part of the code:

     cout << "GCF(" << a;
     cout << "," << b;
     cout << ") => " << endl;

? Thanks in advance.

I'd use `std::cout << "GCF(" << a << ',' << b << ") => \n";`. You can just do it once before the `if`, and indeed the `if` can be replaced by `return b ? gcd(b, a % b) : a;`, which means if `b` is non-0 return `gcd(...)` otherwise `a`. — Tony Delroy, Apr 17 '15 at 02:00
It certainly depends on what you mean by "nicer." You can certainly just use a single `cout` and chain the outputs on a single line if you desire. — Steven Hansen, Apr 17 '15 at 02:00
I was not aware that you could use the nested quotations in that way. Thanks a bunch! — mikeysaxton, Apr 18 '15 at 05:06

score 1 · Answer 1 · answered Apr 17 '15 at 02:03

1

You can do something like:

     cout << "GCF(" << a << ',' << b << ") =>" << endl;

answered Apr 17 '15 at 02:03

l-l

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score 0 · Answer 2 · edited May 23 '17 at 12:06

0

It is not C++ but you could use the C way of printing it which in my opinion looks better in this situation because there are far fewer stream operators, << in the way.

#include <cstdio>

printf("GCF(%d, %d) =>\n", a, b);

But this is a C way of doing things... You could use something like boost::format as is mentioned in this SO answer.

edited May 23 '17 at 12:06

Community

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answered Apr 17 '15 at 05:26

nonsensickle

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I am familiar with the C way of doing things. Thanks a bunch for the responses, guys! – mikeysaxton Apr 18 '15 at 05:05

score 0 · Answer 3 · answered Dec 24 '21 at 04:57

0

try this one

#include<iostream>
#include<conio.h>
using namespace std;

int main(){
  cout << 6+2 <<"\n" << 6-2;
}

answered Dec 24 '21 at 04:57

MD Mahmudul Hasan

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Printing multiple outputs on same line

3 Answers3