How to call PHP function using jquery?

Question

This seems straightforward, but I can't get it to work. I have a button, when it's clicked I'd like to execute a php function which is defined in the same file as the button. My code is below, I get the "clicked" alert when the button is clicked, but no alert on response from the function.

//this is in myfile.php
    <?php
        echo '<button type="button" name="save_button" onclick="save()">Save</button>';
    ?>
        <script type="text/javascript">
            function save() 
            {
              alert("clicked");

              $.ajax({
                url: 'myfile.php',
                type: 'post',
                data: { "set_description": ""},
                success: function(response) { alert(response); }
              });
            }
          </script>

        <?php 
         function set_description() {

          return "a string";
        }
        ?>

How do you get the alert("clicked"); whether at the button the function is named save()? — Wilfredo P, Apr 23 '15 at 20:44
Better to put your PHP into a different file, otherwise you'll get all your HTML in the file as well when you get the response back from AJAX — scrowler, Apr 23 '15 at 20:47

score 1 · Accepted Answer · answered Apr 23 '15 at 21:31

1

Change the type of the jquery Ajax code from post to get since you want to use the response, else I can't see something wrong there

answered Apr 23 '15 at 21:31

Alexander Grasberger

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How to call PHP function using jquery?

1 Answers1