JSON Java 8 LocalDateTime format in Spring Boot

Question

I'm having a small problem with formatting a Java 8 LocalDateTime in my Spring Boot Application. With 'normal' dates I have no problem, but the LocalDateTime fields are converted to the following:

"startDate" : {
    "year" : 2010,
    "month" : "JANUARY",
    "dayOfMonth" : 1,
    "dayOfWeek" : "FRIDAY",
    "dayOfYear" : 1,
    "monthValue" : 1,
    "hour" : 2,
    "minute" : 2,
    "second" : 0,
    "nano" : 0,
    "chronology" : {
      "id" : "ISO",
      "calendarType" : "iso8601"
    }
  }

While I would like convert it to something like:

"startDate": "2015-01-01"

My code looks like this:

@JsonFormat(pattern="yyyy-MM-dd")
@DateTimeFormat(iso = DateTimeFormat.ISO.TIME)
public LocalDateTime getStartDate() {
    return startDate;
}

But either of the above annotations don't work, the date keeps getting formatted like above. Suggestions welcome!

Erik Pragt · Accepted Answer · 2021-10-19T23:12:32.623

158

update: Spring Boot 2.x doesn't require this configuration anymore. I've written a more up to date answer here.

(This is the way of doing it before Spring Boot 2.x, it might be useful for people working on an older version of Spring Boot)

I finally found here how to do it. To fix it, I needed another dependency:

compile("com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.4.0")

By including this dependency, Spring will automatically register a converter for it, as described here. After that, you need to add the following to application.properties:

spring.jackson.serialization.write_dates_as_timestamps=false

This will ensure that a correct converter is used, and dates will be printed in the format of 2016-03-16T13:56:39.492

Annotations are only needed in case you want to change the date format.

edited Oct 19 '21 at 23:12

answered Apr 30 '15 at 05:41

Erik Pragt

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Probably worth including the following annotation - `@JsonSerialize(using = LocalDateTimeSerializer.class)`... – Nick Grealy Jun 28 '16 at 07:40
4

Probably better to just use an `application.properties` entry, as suggested by @patelb answer. – membersound Jun 06 '17 at 07:20
Not working. But patelib's answer just works out of the box! – Mykhaylo Kopytonenko Nov 01 '17 at 14:31
As a heads up, ours needed the `@JsonSerialize` annotation Nick mentioned to get it working. – pennstatephil Mar 06 '18 at 20:11
1

In my case this worked: `@JsonSerialize(using = LocalDateSerializer.class)` and `@JsonFormat(pattern="yyyy-MM-dd")`, no new dependencies and properties. – user3791111 Oct 03 '20 at 09:33
The link in the update part is not working – findusl Dec 15 '20 at 13:13
This version did't solve for me. needed to use `implementation 'com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.13.3'` – Sham Fiorin Jun 11 '22 at 01:51
`Spring Boot 2.x doesn't require this configuration anymore`, this is not true, you still need it. – betteroutthanin Aug 18 '22 at 09:13

score 96 · Answer 2 · edited Jul 11 '20 at 19:41

96

I added the com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.6.1 dependency and started to get the date in the following format:

"birthDate": [
    2016,
    1,
    25,
    21,
    34,
    55
  ]

which is not what I wanted but I was getting closer. I then added the following

spring.jackson.serialization.write_dates_as_timestamps=false

to application.properties file which gave me the correct format that I needed.

"birthDate": "2016-01-25T21:34:55"

edited Jul 11 '20 at 19:41

Saikat

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answered Jan 27 '16 at 07:20

patelb

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2

Worked out of the box when including the `jackson-datatype-jsr310` dependency. This should be the accepted answer. – membersound Jun 06 '17 at 07:19
9

As an FYI, the application.properties part can be done through Java config if you're configuring the ObjectMapper with: `mapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);` – justin Jun 17 '17 at 11:26

score 31 · Answer 3 · edited Oct 07 '18 at 14:12

31

Here it is in maven, with the property so you can survive between spring boot upgrades

<dependency>
        <groupId>com.fasterxml.jackson.datatype</groupId>
        <artifactId>jackson-datatype-jsr310</artifactId>
        <version>${jackson.version}</version>
</dependency>

edited Oct 07 '18 at 14:12

Stefan Falk

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answered May 13 '16 at 20:53

Matt Broekhuis

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2

Use this solution with @NickGrealy comment: Probably worth including the following annotation - `@JsonSerialize(using = LocalDateTimeSerializer.class)` – HairOfTheDog Mar 29 '18 at 19:28

score 26 · Answer 4 · answered Jun 05 '17 at 12:27

1) Dependency

 compile group: 'com.fasterxml.jackson.datatype', name: 'jackson-datatype-jsr310', version: '2.8.8'

2) Annotation with date-time format.

public class RestObject {

    private LocalDateTime timestamp;

    @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    public LocalDateTime getTimestamp() {
        return timestamp;
    }
}

3) Spring Config.

@Configuration
public class JacksonConfig {

    @Bean
    @Primary
    public ObjectMapper objectMapper(Jackson2ObjectMapperBuilder builder) {
        System.out.println("Config is starting.");
        ObjectMapper objectMapper = builder.createXmlMapper(false).build();
        objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
        return objectMapper;
    }
}

Thanks so much. @JsonFormat is the one that solved it for me. None of the above solutions worked for me for some reason — theprogrammer, Feb 11 '20 at 02:11
Is there a similar config for ObjectWriter as I need to convert the object as string and the store to a DB but the LocalDateTime filed comes out as comma seperated. — Sameer, Apr 04 '21 at 15:41

score 14 · Answer 5 · answered Oct 10 '18 at 06:15

14

Writing this answer as a reminder for me as well.

I combined several answers here and in the end mine worked with something like these. (I am using SpringBoot 1.5.7 and Lombok 1.16.16)

@Data
public Class someClass {

   @DateTimeFormat(iso = DateTimeFormat.ISO.DATE_TIME)
   @JsonSerialize(using = LocalDateTimeSerializer.class)
   @JsonDeserialize(using = LocalDateTimeDeserializer.class)
   private LocalDateTime someDate;

}

answered Oct 10 '18 at 06:15

JWiryo

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3

you might want to add imports for `DateTimeFormat` and others. – prayagupa May 12 '19 at 04:11
Where does the LocalDateTimeDeserializer come from? – Martin P. Mar 16 '21 at 20:22
You can check the accepted answer by Erik Pragt, he mentioned he added jackson dependency, that's where it comes from. Hopefully it answers your question – JWiryo Mar 17 '21 at 11:01
1

This solved my problem, thanks. – Faramarz Afzali Dec 12 '21 at 12:48
Glad it helped mate – JWiryo Jan 02 '22 at 17:28

Ida Amit · Answer 6 · 2018-03-17T13:23:39.050

I found another solution which you can convert it to whatever format you want and apply to all LocalDateTime datatype and you do not have to specify @JsonFormat above every LocalDateTime datatype. first add the dependency :

<dependency>
    <groupId>com.fasterxml.jackson.datatype</groupId>
    <artifactId>jackson-datatype-jsr310</artifactId>
</dependency>

Add the following bean :

@Configuration
public class Java8DateTimeConfiguration {
    /**
     * Customizing
     * http://docs.spring.io/spring-boot/docs/current/reference/html/howto-spring-mvc.html
     *
     * Defining a @Bean of type Jackson2ObjectMapperBuilder will allow you to customize both default ObjectMapper and XmlMapper (used in MappingJackson2HttpMessageConverter and MappingJackson2XmlHttpMessageConverter respectively).
     */
    @Bean
    public Module jsonMapperJava8DateTimeModule() {
        val bean = new SimpleModule();

        bean.addDeserializer (ZonedDateTime.class, new JsonDeserializer<ZonedDateTime>() {
            @Override
            public ZonedDateTime deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
                return ZonedDateTime.parse(jsonParser.getValueAsString(), DateTimeFormatter.ISO_ZONED_DATE_TIME);
            }
        });

        bean.addDeserializer(LocalDateTime.class, new JsonDeserializer<LocalDateTime>() {
            @Override
            public LocalDateTime deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
                return LocalDateTime.parse(jsonParser.getValueAsString(), DateTimeFormatter.ISO_LOCAL_DATE_TIME);
            }
        });

        bean.addSerializer(ZonedDateTime.class, new JsonSerializer<ZonedDateTime>() {
            @Override
            public void serialize(
                    ZonedDateTime zonedDateTime, JsonGenerator jsonGenerator, SerializerProvider serializerProvider)
                    throws IOException {
                jsonGenerator.writeString(DateTimeFormatter.ISO_ZONED_DATE_TIME.format(zonedDateTime));
            }
        });

        bean.addSerializer(LocalDateTime.class, new JsonSerializer<LocalDateTime>() {
            @Override
            public void serialize(
                    LocalDateTime localDateTime, JsonGenerator jsonGenerator, SerializerProvider serializerProvider)
                    throws IOException {
                jsonGenerator.writeString(DateTimeFormatter.ISO_LOCAL_DATE_TIME.format(localDateTime));
            }
        });

        return bean;
    }
}

in your config file add the following :

@Import(Java8DateTimeConfiguration.class)

This will serialize and de-serialize all properties LocalDateTime and ZonedDateTime as long as you are using objectMapper created by spring.

The format that you got for ZonedDateTime is : "2017-12-27T08:55:17.317+02:00[Asia/Jerusalem]" for LocalDateTime is : "2017-12-27T09:05:30.523"

Probabaly you need to replace val bean to SimpleModule bean = new SimpleModule(); — Abhishek Galoda, Jan 18 '18 at 17:29
@Abhi, `SimpleModule` extends `Module`. `Module` is an abstract. `val bean = new SimpleModule();` works perfect. — Ida Amit, Mar 17 '18 at 13:16
for SpringBoot version 1.5.3.RELEASE was not necessary to add the jackson-datatype-jsr310 dependency. — Moon13, Apr 24 '18 at 08:23

score 9 · Answer 7 · answered Mar 11 '20 at 08:05

I am using Spring Boot 2.1.8. I have imported

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-json</artifactId>
</dependency>

which includes the jackson-datatype-jsr310.

Then, I had to add these annotations

@JsonSerialize(using = LocalDateTimeSerializer.class)
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
@JsonProperty("date")
LocalDateTime getDate();

and it works. The JSON looks like this:

"date": "2020-03-09 17:55:00"

Hint: including `spring-boot-starter-json` is only needed if `spring-boot-starter-web` is missing. — judomu, May 06 '20 at 10:25

score 8 · Answer 8 · answered Jun 06 '21 at 12:47

8

This worked for me.

I defined birthDate field in my DTO as mentioned below:

@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    private LocalDateTime birthDate;

And in my request body, I passed birthDate in following format :

{
   "birthDate": "2021-06-03 00:00:00"
 }

answered Jun 06 '21 at 12:47

Ruchir Dixit

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1
9

This ```@JsonFormat(pattern="yyyy-MM-dd HH:mm")``` does work. And this does not work with ```yyyy-MM-dd hh:mm``` – Alex Jul 12 '22 at 09:57

score 6 · Answer 9 · answered Jul 05 '18 at 19:38

This work fine:

Add the dependency:

<dependency>
    <groupId>com.fasterxml.jackson.datatype</groupId>
    <artifactId>jackson-datatype-jdk8</artifactId>
</dependency>

Add the annotation:

@JsonFormat(pattern="yyyy-MM-dd")

Now, you must get the correct format.

To use object mapper, you need register the JavaTime

ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());

score 4 · Answer 10 · edited Dec 23 '18 at 22:01

As already mentioned, spring-boot will fetch all you need (for both web and webflux starter).

But what's even better - you don't need to register any modules yourself. Take a look here. Since @SpringBootApplication uses @EnableAutoConfiguration under the hood, it means JacksonAutoConfiguration will be added to the context automatically. Now, if you look inside JacksonAutoConfiguration, you will see:

    private void configureModules(Jackson2ObjectMapperBuilder builder) {
        Collection<Module> moduleBeans = getBeans(this.applicationContext,
                Module.class);
        builder.modulesToInstall(moduleBeans.toArray(new Module[0]));
    }

This fella will be called in the process of initialization and will fetch all the modules it can find in the classpath. (I use Spring Boot 2.1)

score 4 · Answer 11 · answered Dec 07 '20 at 20:13

This worked for me.

import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import com.fasterxml.jackson.datatype.jsr310.deser.LocalDateTimeDeserializer;
import com.fasterxml.jackson.datatype.jsr310.ser.LocalDateTimeSerializer;
public Class someClass {

    @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    @JsonSerialize(using = LocalDateTimeSerializer.class)
    @JsonDeserialize(using = LocalDateTimeDeserializer.class)
    private LocalDateTime sinceDate;

}

score 2 · Answer 12 · edited Mar 16 '22 at 08:45

2

Following Annotations works for me

@JsonSerialize(using = LocalDateSerializer.class) and
@JsonFormat(pattern="yyyy-MM-dd")

edited Mar 16 '22 at 08:45

Procrastinator

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answered Mar 14 '22 at 17:08

Ankush Supnar

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score 1 · Answer 13 · edited Dec 20 '19 at 07:26

I am using Springboot 2.0.6 and for some reason, the app yml changes did not work. And also I had more requirements.

I tried creating ObjectMapper and marking it as Primary but spring boot complained that I already have jacksonObjectMapper as marked Primary!!

So this is what I did. I made changes to the internal mapper.

My Serializer and Deserializer are special - they deal with 'dd/MM/YYYY'; and while de-serializing - it tries its best to use 3-4 popular format to make sure I have some LocalDate.

@Autowired
ObjectMapper mapper;

@PostConstruct
public ObjectMapper configureMapper() {
    mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);
    mapper.enable(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT);

    mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
    mapper.configure(SerializationFeature.ORDER_MAP_ENTRIES_BY_KEYS, true);

    mapper.configure(MapperFeature.ALLOW_COERCION_OF_SCALARS, true);
    mapper.configure(MapperFeature.SORT_PROPERTIES_ALPHABETICALLY, true);

    SimpleModule module = new SimpleModule();
    module.addDeserializer(LocalDate.class, new LocalDateDeserializer());
    module.addSerializer(LocalDate.class, new LocalDateSerializer());
    mapper.registerModule(module);

    return mapper;
}

score 0 · Answer 14 · edited Sep 27 '18 at 15:48

@JsonDeserialize(using= LocalDateDeserializer.class) does not work for me with the below dependency.

<dependency>
    <groupId>com.fasterxml.jackson.datatype</groupId>
    <artifactId>jackson-datatype-jsr310</artifactId>
    <version> 2.9.6</version>
</dependency>

I have used the below code converter to deserialize the date into a java.sql.Date.

import javax.persistence.AttributeConverter;
import javax.persistence.Converter;


@SuppressWarnings("UnusedDeclaration")
@Converter(autoApply = true)
public class LocalDateConverter implements AttributeConverter<java.time.LocalDate, java.sql.Date> {


    @Override
    public java.sql.Date convertToDatabaseColumn(java.time.LocalDate attribute) {

        return attribute == null ? null : java.sql.Date.valueOf(attribute);
    }

    @Override
    public java.time.LocalDate convertToEntityAttribute(java.sql.Date dbData) {

        return dbData == null ? null : dbData.toLocalDate();
    }
}

score 0 · Answer 15 · answered Apr 27 '21 at 16:07

Added

group: 'com.fasterxml.jackson.datatype', name: 'jackson-datatype-jsr310', version: '2.8.8'

into gradle compile block

and in the application.yml file

spring:
  jackson:
    serialization:
      write_dates_as_timestamps: false

if you are using application.properties file add the following

spring.jackson.serialization.write_dates_as_timestamps=false

in case you want to apply a custom format you can apply the annotation

    @JsonFormat(pattern = "yyyy-MMMM-dd hh:mm:ss")
    private LocalDateTime date;

It started working fine for me

score -2 · Answer 16 · edited Apr 29 '19 at 06:45

-2

simply use:

@JsonFormat(pattern="10/04/2019")

or you can use pattern as you like for e.g: ('-' in place of '/')

edited Apr 29 '19 at 06:45

vimuth

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answered Apr 29 '19 at 06:30

Ashish Dwivedi

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This answer has been shared before, but then with the correct syntax. – Erik Pragt Apr 30 '19 at 07:35

JSON Java 8 LocalDateTime format in Spring Boot

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