How to return array in c?

Question

How to return array in C?

    #include <stdio.h>
    #include <string.h>
    #include <stdlib.h>

    int main()

    {
        int func(int);
        printf("%d",func(1));

    }

    int func(int n)
    {
        int i,arr[5]; //or int *arr=(int*)malloc(5);
        for (i=0; i<5; i++) {
            arr[i]=n++;
        }
        return arr;
    }

I want to get result '11111', but this code's result is '1606416336'.
What can I do to solve this problem?

You can't return a local array in C. You need to allocate it dynamically with `malloc()`. — Barmar, May 05 '15 at 00:14
http://www.tutorialspoint.com/cprogramming/c_return_arrays_from_function.htm — Robert Harvey, May 05 '15 at 00:15
You can't *ever* return an array in C. It's an annoying limitation. You can, however, return a struct that contains an array, or have the caller create an array and pass a pointer to it as an argument. — user253751, May 05 '15 at 00:15
`int func(int n) { int i, v = 0; for (i=0; i<5; i++) { v = v * 10 + n; } return v; }` — BLUEPIXY, May 05 '15 at 00:16
Robert Harvey// Wow!!Thanks very much!! It can be help me a lot!! — Kate, May 05 '15 at 01:07

score 0 · Accepted Answer · answered May 05 '15 at 00:45

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int *func1(int);
    int func2(int);
    int *p = func1(1);
    int i;
    for(i=0; i < 5; ++i){
        printf("%d", p[i]);
    }
    printf("\n");
    free(p);

    printf("%d",func2(1));
    return 0;
}

int *func1(int n){
    int i;
    int *arr=(int*)malloc(5*sizeof(int));
    for (i=0; i<5; i++) {
        arr[i]=n;
    }
    return arr;
}

int func2(int n){
    int i, v = 0;
    for (i=0; i<5; i++){
        v = v * 10 + n;
    }
    return v;
}

How to return array in c?

1 Answers1