Get Fruits with Highest value in object

Question

Let me know how to get the highest values for my variable Result in this event for example : if MyFruits ={ "Orange": 1, "Banana": 3, "Apple": 3 }

I would like to get "Banana" and "Apple" but It gives me only the first fruit : "Banana"

 // first the variable MyFruits must have index 0
 // and after the user clicks to give value.
 var MyFruits = {
     "Orange": 0,
     "Banana": 0,
     "Apple": 0
 };
 $('input:checked').each(function(index) {
     var key = $(this).val();
     if (key in MyFruits) {
         MyFruits[key]++;
     } else {
         MyFruits[key] = 1;
     }
 });
 var Result = Object.keys(MyFruits).reduce(function(a, b) {
     return MyFruits[a] > MyFruits[b] ? a : b
 });

First, my var "MyFruits" needs a index 0 for each fruit. Then the index changes when user clicks on radio button. — bao bao, May 11 '15 at 13:54

Salman A · Answer 1 · 2015-05-11T13:59:46.060

Flip your object such that the numbers 1, 3, 3... become keys and their value is an array of corresponding fruits:

var MyFruits = { "Orange": 1, "Banana": 3, "Apple": 3 };
var FruitsValue = {};
var MaxValue = -1;
$.each(MyFruits, function(friut, value) {
    if (FruitsValue[value] === undefined) {
        FruitsValue[value] = [];
    }
    FruitsValue[value].push(friut)
    MaxValue = Math.max(MaxValue, value);
});
console.log(FruitsValue);
// {1: ["Orange"], 3:["Banana","Apple"]}
console.log(FruitsValue[MaxValue]);
// ["Banana", "Apple"]

score 0 · Answer 2 · answered May 11 '15 at 13:52

0

Try this:

var max = 0;
var maxProp = null;
for (var property in MyFruits) {
   if (max < MyFruits[property])
   {
      max = MyFruits[property];
      maxProp = property;
   }
}

answered May 11 '15 at 13:52

suvroc

3,058
1
15
29

user2808054 · Answer 3 · 2015-05-11T13:56:16.483

0

think you have to do two passes ..

var MyFruits ={ "Orange": 1, "Banana": 3, "Apple": 3 };
var highest=0;
var results = [];
//pass 1 : find highest
for (f in MyFruits)
{
    if (MyFruits[f] > highest) { highest = MyFruits[f] ) }
}

// pass 2 : find all which match highest
for (f in MyFruits[f]) {
  if (MyFruits[f] == highest) {results.push(MyFruits[f])}

}

array 'results' ends up with array of all that match the highest value

edited May 11 '15 at 13:56

answered May 11 '15 at 13:53

user2808054

1,376
1
11
19

1

Is this supposed to be JavaScript? – Felix Kling May 11 '15 at 13:55
@FelixKling Woops sorry, I've been on holiday. Got my languages mixed up. Hopefully makes more sense now. – user2808054 May 11 '15 at 13:58

score 0 · Answer 4 · edited May 23 '17 at 11:58

Similar question to: How can I order the items in an Object?

You can get the ordered result set like this:

var res = Object.keys(MyFruits).map(function(key ) {
  return { key: key, value : dict[key] };
}).sort(function(a, b) { 
   return b.value - a.value
});

The first index res[0] has the biggest object in format

  { key : "Banana", value : 3}

And the second highest in res[1] and so on...

score 0 · Accepted Answer · answered May 11 '15 at 13:59

You need to keep elements if they are same. You can use temporary array for this.

var MyFruits ={ "Orange": 1, "Banana": 3, "Apple": 3 };
                $('input:checked').each(function(index) {
                    var key = $(this).val();
                    if (key in MyFruits) {
                        MyFruits[key]++;
                    } else {
                        MyFruits[key] = 1;
                    }
                });


var resultArray = [];
var Result = Object.keys(MyFruits).reduce(function(a, b) {
                if( MyFruits[a] == MyFruits[b] ) {
                    resultArray.push(b);
                    return a;  
                }

                 var bigger = MyFruits[a] > MyFruits[b] ? a : b;
                 resultArray = [];
                 resultArray.push(bigger);
                 return bigger;
            })

score 0 · Answer 6 · answered May 11 '15 at 14:01

0

User .filter() instead of .reduce().

Here is the example:

Object.keys(MyFruits).filter(function (a, b) {
    return MyFruits[a] > MyFruits[b] ? a : b;
});

Otherwise your condition does great work! Happy Coding...!!

answered May 11 '15 at 14:01

Ashish Kumar

2,991
3
18
27

Get Fruits with Highest value in object

6 Answers6