creating the sequence 000,111,222 ... in c++

Question

I want my std::cout to print 000111222333 ..., but what i'm getting instead is 0111222333 ..., and i don't know why, here is my code:

int threeCounter =1;
int outPut =0;
for (int i =0; i<300;i++){

    if(threeCounter > 3 ){
        outPut++ ;
        threeCounter=1;

    }

    cout << outPut << endl;
    threeCounter++;

}

I tried the very same code in matlab, and it's producing the correct sequence:

threeCounter=1;
outPut =0;
for i =1:300

    if(threeCounter >3)

        outPut=outPut+1;
        threeCounter=1;

    end
    disp(outPut)
    threeCounter=threeCounter+1;

end

The "very same" code? It´s not. And stop thinking that all languages have same semantics. — deviantfan, May 15 '15 at 20:05
The leading zeros of numbers may not get displayed. See the `fill` I/O manipulator. — Thomas Matthews, May 15 '15 at 20:06
If you change your printout to before the `if` condition, everything then works as intended except you do not print the third `99`, so you're left with `98 98 98 99 99`. This makes sense since it will not iterate the loop the third time, but may be a clue as to why you do not get the initial `0`. — Javia1492, May 15 '15 at 20:19
@ shruti1810 No, it didn't compile, an error about to_string poped out, when i looked it out, i found that it's a known bug for MinGW to not take to_string as a member of std, Anyway, the code i posted was correct, the display via cout was omitting the first zeros, so thanks anyway! — Apastrix, May 15 '15 at 20:28

shruti1810 · Answer 1 · 2015-05-15T20:23:01.993

0

Try this code in C++:

#include <iostream>
#include <string>
using namespace std;

int main()
{
for (int i =0; i<300;i++){
   string outPut = "";
   int threeCounter =0;
    while(threeCounter < 3 ){
        outPut = outPut+to_string(i) ;
        threeCounter+=1;

    }

    cout << outPut;
    threeCounter++;

}

}

edited May 15 '15 at 20:23

answered May 15 '15 at 20:12

shruti1810

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The `to_string` is not available before C++11. Tell your compiler to use C++11 features. – Thomas Matthews May 15 '15 at 20:25

creating the sequence 000,111,222 ... in c++

1 Answers1