Substring at flask template

Question

I have a loop to show a list content in a flask template but I don't want to show the first character of the element , in this way works in python but not in flask

{%for file in files%}
        {% f= file['path'] %}
        <p> {{ f[1:] }}</p>
{% endfor %}

I get this error

TemplateSyntaxError: Encountered unknown tag 'f'. Jinja was looking for the following tags: 'endfor' or 'else'. The innermost block that needs to be closed is 'for'.

score 6 · Accepted Answer · answered May 17 '15 at 17:14

6

You need to set variables if you wish to use them in that way. (Documentation).

That said— you should be able to just do {{ file['path'][1:] }} within your for loop.

answered May 17 '15 at 17:14

Doobeh

9,280
39
32

score 3 · Answer 2 · edited May 23 '17 at 11:54

3

Duplicate of this question.

You have to use the {% set %} template tag to assign variables within a jinja2 template:

{% for file in files %}
    {% set f = file['path'] %}
    <p>{{ f[1:] }}</p>
{% endfor %}

edited May 23 '17 at 11:54

Community

1
1

answered May 17 '15 at 17:18

Michael Blakeley

346
1
7

1

That being said, Doobeh has the right idea: just taking a slice of the dict value avoids this problem altogether. – Michael Blakeley May 17 '15 at 17:21

Substring at flask template

2 Answers2