Why is my normal 'if' statement not working on python

Question

I am trying make a maths game but the output says wrong when I answer it correctly. (on python 2.7.2) The code:

import random
number1 = random.randrange(1, 10)
number2 = random.randrange(1, 10)
print "Whats",number1,"+",number2
answer = raw_input('=')
if answer is (number1 + number2):
    print "Correct!"
else:
    print "Wrong!"

Also, `answer = int(raw_input('='))` will work, because right now it is reading in the users input as a string — heinst, May 19 '15 at 18:16
See 'is' vs' '=='. http://stackoverflow.com/questions/1504717/why-does-comparing-strings-in-python-using-either-or-is-sometimes-produce — Alexander, May 19 '15 at 18:31

score 3 · Answer 1 · edited May 23 '17 at 12:14

3

You want to use == instead of is. is is used for checking reference equality. You can look at this for a better explanation. raw_input reads values in as strings by default, so you need to convert it to an integer to be able to check if the input is equal to the answer. Or more simply, use input instead.

import random
number1 = random.randrange(1, 10)
number2 = random.randrange(1, 10)
print "Whats",number1,"+",number2
answer = input('=')
if answer == (number1 + number2):
    print "Correct!"
else:
    print "Wrong!"

edited May 23 '17 at 12:14

Community

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answered May 19 '15 at 18:16

heinst

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I have a lot more experience with coding and this seems like a stupid mistake! Thanks anyway! – JackHumphries Oct 27 '17 at 09:04

Why is my normal 'if' statement not working on python

1 Answers1