Why doesn't this php work?

Question

So I got this code from codeacademy. It's supposed combine php, html and css to randomly output a coin-styled div in a while loop as long as the result is heads. However, It's not working, all the php is showing and I have no clue why.

.coin {
    height: 50px;
    width: 50px;
    border-radius: 25px;
    background-color: grey;
 text-align: center;
 font-weight: bold;
 font-family: sans-serif;
 color: white;
 margin: 10px;
 display: inline-block;
 line-height: 50px;
 font-size: 20px;
}

<!DOCTYPE html>
<html>
    <head>
     <link type='text/css' rel='stylesheet' href='style.css'>
  <title>More Coin Flips</title>
 </head>
 <body>
 <p>We will keep flipping a coin as long as the result is heads!</p>
 <?php
 $flipCount = 0;
 do {
  $flip = rand(0,1);
  $flipCount ++;
  if ($flip){
   echo "<div class="coin">H</div>";
  }
  else {
   echo "<div class="coin">T</div>";
  }
 } while ($flip);
 $verb = "were";
 $last = "flips";
 if ($flipCount == 1) {
  $verb = "was";
  $last = "flip";
 }
 echo "<p>There {$verb} {$flipCount} {$last}!</p>";
 ?>
    </body>
</html>

you need to configure webserver like `wamp` or `xampp` to your machine. — viral, May 25 '15 at 09:55
error ? did you configure or install a wamp/lamp/mamp ? basically can you run php ? — Jigar, May 25 '15 at 09:56
`the php is showing and I have no clue why` php isn't enabled or extension isn't right. — Jigar, May 25 '15 at 09:58
Do you even have a localhost webserver or any server to run the code ? — Mohamed Belal, May 25 '15 at 09:58
what is the extension of your file? Assuming your `xampp` is running, is this file in `htdocs` directory ? what is the url you are accessing ? — viral, May 25 '15 at 10:01
In your echo you make "
" you have to escape the " it would be like this echo "
" — Mohamed Belal, May 25 '15 at 10:02

Fracsi · Answer 1 · 2016-01-13T09:05:43.770

0

The problem is closing a quotation in the while loop near "div"...

The correct PHP would be:

<?php
$flipCount = 0;
do {
    $flip = rand(0,1);
    $flipCount ++;
    if ($flip){
        echo "<div class='coin'>H</div>";
    }
    else {
        echo "<div class='coin'>T</div>";
    }
} while ($flip);
$verb = "were";
$last = "flips";
if ($flipCount == 1) {
    $verb = "was";
    $last = "flip";
}
echo "<p>There {$verb} {$flipCount} {$last}!</p>";
?>

Note the single quote around 'coin'.

edited Jan 13 '16 at 09:05

answered May 25 '15 at 09:56

Fracsi

2,274
15
24

Lmao I'm an idiot. No wonder I got the downvotes. Thanks fam – Anjunadeep May 25 '15 at 13:51

score 0 · Answer 2 · answered May 25 '15 at 09:58

<!DOCTYPE html>
<html>
<head>
    <link type='text/css' rel='stylesheet' href='style.css'>
    <title>More Coin Flips</title>
</head>
<body>
<p>We will keep flipping a coin as long as the result is heads!</p>
<?php
$flipCount = 0;
do {
    $flip = rand(0,1);
    $flipCount ++;
    if ($flip){
        echo '<div class="coin">H</div>';
    }
    else {
        echo '<div class="coin">T</div>';
    }
} while ($flip);
$verb = "were";
$last = "flips";
if ($flipCount == 1) {
    $verb = "was";
    $last = "flip";
}
echo "<p>There {$verb} {$flipCount} {$last}!</p>";
?>
</body>
</html>

qoute mismatch in echo '<div class="coin">H</div>';

Yes, but this would not cause the problem as described. It would trigger a *syntax error*. — deceze, May 25 '15 at 10:23

score 0 · Answer 3 · edited Sep 19 '18 at 10:03

Use this:-

<!DOCTYPE html>
<html>
<head>
    <link type='text/css' rel='stylesheet' href='style.css'>
    <title>More Coin Flips</title>
</head>
<body>
<p>We will keep flipping a coin as long as the result is heads!</p>
<?php
$flipCount = 0;
do {
    $flip = rand(0,1);
    $flipCount ++;
    if ($flip){
        echo "<div class='coin'>H</div>";
    }
    else {
        echo "<div class='coin'>T</div>";
    }
} while ($flip);
$verb = "were";
$last = "flips";
if ($flipCount == 1) {
    $verb = "was";
    $last = "flip";
}
echo "<p>There {".$verb."} {".$flipCount."} {".$last."}!</p>";
?>
</body>

Why doesn't this php work?

3 Answers3