if condition not working properly inside a function python 3

Question

This is the following code.The test2 function doesnt get invoked why? Even if i enter 1 the test2 fuction is not called

def test2():
    print("here i come")
def test1():
    x=input("hey ill take u to next fuction")
    if(x==1):
      test2()
test1()

Answer 1

x=input("hey ill take u to next fuction")

x will be a string type, not an integer. You should change the if statement to compare the same types (either converting x to int, or 1 to "1"

Answer 2

Because you are comparing a string (your input) with 1 that is a integer.So you need to convert the input to int and then compare it.

Also as it can raise ValueError you can use a try-except to handle that :

def test1():
    x=input("hey ill take u to next fuction")
    try :
       if(int(x)==1):
          test2()
    except ValueError:
       print 'enter a valid number'