Comparing two string in Java not giving the expected result

Question

I am beginner i want to get text in EditText and compare it with another string .

I want to check if text writed in EditText is equals a 'String' then show a Toast but it is not working

I debug and check the value of both are exactly admin but if block is not working and shows else block.

if (editText.getText().toString() == "admin") {
    //Never enter this block when i type "admin" in the EditText.
    Toast.makeText(MainActivity.this,"ok",Toast.LENGTH_LONG).show();
} else {
    Toast.makeText(MainActivity.this,"Wrong User Or Pass",
}

Answer 1

You have to use String.equals() method for string matching.

Change your code into this

    if (editText.getText().toString().equals("admin")) {
        //your code
    }

.

Answer 2

do not use == to compare strings since strings are not primitive data types instead use user.equals("admin")

Answer 3

You can user equalsIgnoreCase.

This method compares this String to another String, ignoring case considerations. Two strings are considered equal ignoring case if they are of the same length, and corresponding characters in the two strings are equal ignoring case.

    btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {


            if (user.equalsIgnoreCase("admin")) {
Toast.makeText(MainActivity.this,"ok",Toast.LENGTH_LONG).show();

            }
            else {
                Toast.makeText(MainActivity.this,"Wrong User Or Pass",Toast.LENGTH_LONG).show();
                Toast.makeText(MainActivity.this,user,Toast.LENGTH_LONG).show();

            }

    });

Answer 4

When i use this way i solved my problem.

  boolean result = String1.equals(String2);
    if (result)
    {
        return  true;
    }
    else
    {
        return  false;
    }