PHP: Create custom filter_var() constants

Question

How would i go about creating custom filters for use in PHP filter_var().

An example:

Right now i have a function to validate a date:

    private function validateDate($date){
        $d = DateTime::createFromFormat('Y-m-d', $date);
        return $d && $d->format('Y-m-d') == $date;
    }

^{function was copied from this answer or php.net}

I want to be able to call a constant like FILTER_VALIDATE_DATE and have it checked by the above code.

Any help is appreciated.

You can't. But you can pass in a callback / closure. Why don't you just make your own function like `filter_date()`? — Jocke Med Kniven, Jun 30 '15 at 18:43

score 3 · Answer 1 · answered Jun 30 '15 at 19:51

PHP does not have a way for you to register a custom filter, so you can't simply make a new constant to pass in. The best thing you can do is use the FILTER_CALLBACK and pass the callback in as the third argument, like so:

$valid = filter_var($date, FILTER_CALLBACK, ['options' => 'validateDate']);

Kristian Vitozev · Answer 2 · 2015-06-30T18:48:17.957

0

You should use filter callback functions.

$date = "2015-06-30";

echo filter_input( $date, FILTER_CALLBACK, array('options' => 'validateDate') );

edited Jun 30 '15 at 18:48

answered Jun 30 '15 at 18:43

Kristian Vitozev

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PHP: Create custom filter_var() constants

2 Answers2