Parse error: syntax error, unexpected '!'

Question

This is my php code

<?php   
    if ($_POST['submit']){
        if (!$_POST['email']) $error.="</br>Please enter your email address";
        else if !(filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) $error = "</br>Please enter a valid email address.";

     if (!$_POST['password']) $error.="</br>Please enter a password.";

   if($error) echo "There were error(s)".$error;
  }
?>

I don't find any mistake there. But it is showing this error

Parse error: syntax error, unexpected '!', expecting '(' in C:\xampp\phpMyAdmin\abc\projects\s_diary.php on line 5

I am not much experienced in php. So, please help me...

check this line : `if !(filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) ` put `!` inside bracket. First write the code properly using identations .. — Makesh, Jul 02 '15 at 06:03
@Maruf please mark and up-vote the answer for others help. thanks — Alive to die - Anant, Feb 03 '16 at 19:44
people are not interested in marking answer as accepted. Wastage of time and effort. deleting my answer. — Alive to die - Anant, Apr 15 '16 at 04:58

score 1 · Answer 1 · answered Jul 02 '15 at 06:05

The first else if is missing parentheses around its if-expression, as in:

else if ( !(filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) ) ...
        ^                                                       ^
        |                                                       |

Parse error: syntax error, unexpected '!'

1 Answers1