I have some confusion regarding below program. here I got output as 128.
int i=0;
while(Integer.valueOf(i)==Integer.valueOf(i))
i++;
System.out.println(i);
output: 128
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Musaddique
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Exactly. To figure it our yourself, change `valueOf` to `parseInt` and see what happens. – Emad Y Jul 05 '15 at 08:16
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@ user3469481 here parseInt won't work. as i is int. – Musaddique Jul 09 '15 at 12:45
1 Answers
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The JVM caches int values between -128 and 127 for the Integer class. Therefore, the following statement will return true upto 127 :
Integer.valueOf(i)==Integer.valueOf(i)
Beyond 127, valueOf returns a new Integer object by default.
On the last iteration of your while loop, i will be 127 and i++ will change it to 128. That's why the output is 128 and not 127.
Chetan Kinger
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