BASH: make an array of all directory names in a directory that DON'T have a certain pattern in the name

Question

I have a directory that contains a bunch of .zip files as well as their unpacked version. I need to get a list of all the directory's and ignore the .zip files. How can I do this?

I am thinking of using grep and ls, but am not sure how to put it together.

related: http://stackoverflow.com/questions/3548453/negative-matching-using-grep-match-lines-that-do-not-contain-foo — NightShadeQueen, Jul 07 '15 at 19:23
Parsing `ls` is fragile and unsafe. See [Pattern Matching](http://www.gnu.org/software/bash/manual/bashref.html#Pattern-Matching) specifically the bottom section about `extglob`. — Etan Reisner, Jul 07 '15 at 19:23
and to store it in an array? would it be myarr=$(ls | grep -v "\.zip")? — farid99, Jul 07 '15 at 19:24
@EtanReisner so how would you do it? Getting the list of filenames I described? — farid99, Jul 07 '15 at 19:24

score 6 · Accepted Answer · answered Jul 07 '15 at 19:25

6

Get a list of all sub-directories and store it into an array:

shopt -s nullglob
dirs=( */ )

answered Jul 07 '15 at 19:25

anubhava

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I used this, but then when I tried `echo $dirs` all I got was one out of the many subdirectories in the working directory. – farid99 Jul 07 '15 at 19:32
5

You need to use `echo "${dirs[@]}"` to list all directories. – anubhava Jul 07 '15 at 19:33

score 5 · Answer 2 · answered Jul 07 '15 at 19:26

5

If you can turn on extglob like so:

shopt -s extglob
declare -a files=( !(*.zip) )

See more about bash pattern matching on the Pattern Matching man page.

answered Jul 07 '15 at 19:26

Jeff Bowman

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BASH: make an array of all directory names in a directory that DON'T have a certain pattern in the name

2 Answers2