passing 2d float array to a function in C++

Asked Aug 12 '15 at 07:37

Active Aug 12 '15 at 07:51

Viewed 42 times

I am trying to pass a 2D array to a function following is my code.

float solve(float arr[(nsamples*numImages)+255][256 + nsamples]){
    return 0;
}

int main(){
    nsamples = 100;
    numImages = 5;
    float arr[ (nsamples*numImages)+255][256 + nsamples];
    float res = solve(arr);
    return 0;
}

nsamples and numImages are globals. I am getting the following error

candidate function not viable: no known conversion from
      'float [(nsamples * numImages) + 255][256 + nsamples]' to 'float (*)[256 +
      nsamples]' for 1st argument
int solve(float arr[(nsamples*numImages)+255][256 + nsamples]){

I have tried the variations given here but nothing worked.

edited May 23 '17 at 12:14

Community

asked Aug 12 '15 at 07:37

graphics_master

Questions of this sort get asked *every day*. Please search before asking. – dandan78 Aug 12 '15 at 07:42
I think you will need to have an integer constant in the second dimension of arr and not `256+nsamples`. – j809 Aug 12 '15 at 07:54
(@j809) VLA's don't even exist in C++, so both dimensions must be constant expressions. – Quentin Aug 12 '15 at 08:05

passing 2d float array to a function in C++

0 Answers0