I'll try to help with the forgotten Could someone explain this part of the question.
register __m128i xmm0, xmm1;
register unsigned int eax;
Here we declare some variables. __m128i is a builtin type for integer operations on SSE registers. Note that the names of the variables do not matter at all, but the author has named them exactly as the corresponding CPU registers are called in assembly. xmm0, xmm1, xmm2, xmm3, ... are all the registers for SSE operations. eax is one of the general-purpose registers.
register keyword was used long time ago to advise compiler to place variable in a CPU register. Today it is completely useless, I think. See this question for details.
xmm0 = _mm_loadu_si128((__m128i*)(a));
xmm1 = _mm_loadu_si128((__m128i*)(b));
This code was modified as @harold suggested. Here we load 16 bytes from given memory pointers, which may be unaligned) to variables xmm0 and xmm1. In assembly code these variables most likely would be located directly in registers, so this intrinsics would generate unaligned memory load. Converting pointer to __m128i* type is necessary because intrinsic accepts this pointer type, though I have no idea why Intel did it.
xmm0 = _mm_cmpeq_epi8(xmm0, xmm1);
Here we compare for equality each byte from xmm0 variable with corresponding byte in xmm1 variable. Suffix _epi8 means operating on 8-bit elements, i.e. bytes. It is somewhat similar to memcmp(&xmm0, &xmm1, 16), but generates other results. It returns a 16-byte value, which contains 0xFF for each byte with equal values, and 0x00 for each byte with different values.
eax = _mm_movemask_epi8(xmm0);
This is a very important instruction from SSE2, which is usually used to write an if statement with some SSE condition. It takes the highest bit from each of 16 bytes in XMM argument, and writes them into a single 16-bit integer number. On assembly level, this number is located in general-purpose register, allowing us to check its value quickly just afterwards.
if(eax==0xffff) //equal
else //not equal
If all the 16 bytes of two XMM registers were equal, then _mm_cmpeq_epi8 must return a mask with all 128 bits set. _mm_movemask_epi8 would then return full 16-bit mask, which is 0xFFFF. If any two compared bytes were different, corresponding byte would be filled with zeros by _mm_cmpeq_epi8, so _mm_movemask_epi8 would return 16-bit mask with corresponding bit not set, so it would be less than 0xFFFF.
Also, here is the explained code wrapped into a function:
bool AreEqual(const char *a, const char *b) {
__m128i xmm0, xmm1;
unsigned int eax;
xmm0 = _mm_loadu_si128((__m128i*)(a));
xmm1 = _mm_loadu_si128((__m128i*)(b));
xmm0 = _mm_cmpeq_epi8(xmm0, xmm1);
eax = _mm_movemask_epi8(xmm0);
return (eax == 0xffff); //equal
}