Java Converting String to Integer

Question

I have the following codes below:

    private Integer mTarifId;

    public Integer getTarifId() {
        return mTarifId;
    }

    public void setTarifId(Integer tarifId) {
        this.mTarifId = tarifId;
    }

I have initialized a variable named 'mTarifId'. And i need to use it in the code below.

if (!Objects.equals(mTarifId, null)) {
            query = mEntityManager.createQuery("FROM TarifListeCalendrierEntity WHERE tarifListeId=:pId")
                    .setParameter("pId", mTarifId);
            List<TarifListeCalendrierEntity> tarifListCalendrierList = query.getResultList();
            if (!tarifListCalendrierList.isEmpty()) {
                TarifListeCalendrierEntity tarifListCalendrier = tarifListCalendrierList.get(0);
                request.setAttribute("tarif_list_calendrier", tarifListCalendrier);
            }
        }

But in order to do so i need to convert it to an integer in the 'doGet'

        String tarifId = request.getParameter("tarifid");

        if (!Objects.equals(tarifId, null)) {
            setTarifId(Integer.valueOf(tarifId));
        }else {
            setTarifId(null);
        }

Please help identify what i'm doing wrong.

When debugging this line of code is skipped 'if (!Objects.equals(mTarifId, null)) {' meaning the value of mTarifId is still null. — Fadil, Aug 18 '15 at 09:55
a friend told me to use something like this to get the value in mTarifId mTarifId = request.getParameter("tarifid") But when doing so i'm getting the error incompatible types: String cannot be converted to Integer — Fadil, Aug 18 '15 at 09:59
please focus on the main issue you are facing, is it getting null request parameter? — Amit.rk3, Aug 18 '15 at 10:07
possible duplicate of [Converting String to int in Java?](http://stackoverflow.com/questions/5585779/converting-string-to-int-in-java) — bhdrkn, Aug 18 '15 at 10:29

score 0 · Answer 1 · answered Aug 18 '15 at 09:58

0

Every time else condition is executed that why it's null.

String tarifId = request.getParameter("tarifid");

        if (tarifId!=null)

For Typecasting String to Integer.

Integer.parseInt(String);

answered Aug 18 '15 at 09:58

Man Programmer

5,300
2
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21

I'm confused, please be more specific – Fadil Aug 18 '15 at 10:02
Change your if condition as i mentioned and let me know. – Man Programmer Aug 18 '15 at 10:03
I modified it as suggested String tarifId = request.getParameter("tarifid"); if (tarifId!=null) { setTarifId(Integer.valueOf(tarifId)); } else { setTarifId(null); } codes still skipped while debugging – Fadil Aug 18 '15 at 10:04
Print your tarifId, may be it came null – Man Programmer Aug 18 '15 at 10:06
i made a System.out.print(tarifId); but im not able to see the output in my wildfly console. can you help please.. – Fadil Aug 18 '15 at 10:40
It may be blank string. Please make sure if its not blank. – SacJn Aug 18 '15 at 10:54

score 0 · Answer 2 · answered Aug 18 '15 at 10:08

can you maybe use try catch if there is any NumberFormatException.

Try this:

String tarifId = request.getParameter("tarifid");
Integer number;
try{
    number = Integer.valueOf(tarifId);
} catch(NumberFormatException e){
    number = 0;
}
setTarifId(number)

Also, do you need your setTarifId() expecting an Integer, or int could be fine?

score 0 · Answer 3 · answered Aug 18 '15 at 10:26

0

Your actual issue is your request parameter. It may happen that your mTarifId is not even set in request parameter named tarifid.

You have not mentioned how do you set it. So check that code if this parameter is actually set or not.

answered Aug 18 '15 at 10:26

SacJn

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1
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you are right...this is how it should be set i think mTarifId = Integer.valueOf(request.getParameter("tarifid")); – Fadil Aug 18 '15 at 10:38
It would throw **NUMBER FORMAT EXCEPTION** in case request,getParameter("tarifId") returns null or blank. – SacJn Aug 18 '15 at 10:57

score 0 · Answer 4 · answered Aug 18 '15 at 11:13

0

This was what i needed:

mTarifId = Integer.valueOf(request.getParameter("tarifid"));

answered Aug 18 '15 at 11:13

Fadil

57
2
8

Instead of reposting another user's answer, you should simply upvote and/or accept their answer. – durron597 Aug 18 '15 at 13:40

Java Converting String to Integer

4 Answers4