How to set the prototype of a function?

Question

Something like this, but not using __proto__:

var o = {
    i :2
}; 

var f1 = function(){
    alert(f1.i);
} 

f1.__proto__ = o; 

o.i = 3; 

f1(); //3

When I see such questions I always wonder: why do you people intentionally try to make your code as hard for understanding and maintenance as possible? — zerkms, Aug 21 '15 at 07:53
@D_Pavel: You're trying to set the internal prototype of a function object that doesn't yet exist? — Bergi, Aug 21 '15 at 08:27
@D_Pavel: why "*like this, but not using `__proto__`*"? What are you trying to do here in the first place, what is your use case? — Bergi, Aug 21 '15 at 08:28
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/87574/discussion-between-d-pavel-and-bergi). — D_Pavel, Aug 21 '15 at 09:40

score 0 · Answer 1 · answered Aug 21 '15 at 08:07

0

One method is using bind API. So your Javascript looks like this

var o = {i :2}; 
var f1 = function(){    alert(this.i);    }.bind(o)
o.i = 3; 
f1(); //3

answered Aug 21 '15 at 08:07

NiRUS

bind not set the `__proto__` – D_Pavel Aug 21 '15 at 08:21
1

@D_Pavel and in your question you did not ask to set it. – zerkms Aug 21 '15 at 21:58

1 Answers1