how to delete empty dict inside list of dictionary?

Question

How can I remove empty dict from list of dict as,

{
 "ages":[{"age":25,"job":"teacher"},
         {},{},
         {"age":35,"job":"clerk"}
        ]
}

I am beginner to python. Thanks in advance.

Use a list comprehension within a dict comprehension , `{k:[i for i in v if i] for k,v in d.items()}` — Mazdak, Aug 24 '15 at 11:19

score 18 · Accepted Answer · answered Aug 24 '15 at 11:19

Try this

In [50]: mydict = {
   ....:  "ages":[{"age":25,"job":"teacher"},
   ....:          {},{},
   ....:          {"age":35,"job":"clerk"}
   ....:         ]
   ....: }

In [51]: mydict = {"ages":[i for i in mydict["ages"] if i]}

In [52]: mydict
Out[52]: {'ages': [{'age': 25, 'job': 'teacher'}, {'age': 35, 'job': 'clerk'}]}

OR simply use filter

>>>mylist = [{'age': 25, 'job': 'teacher'}, {}, {}, {'age': 35, 'job': 'clerk'}]
>>>filter(None, mylist)
[{'age': 25, 'job': 'teacher'}, {'age': 35, 'job': 'clerk'}]

So in your dict, apply it as

{
 "ages":filter(None, [{"age":25,"job":"teacher"},
         {},{},
         {"age":35,"job":"clerk"}
        ])
}

This will no longer work in Python3, use generator-expressions instead: http://stackoverflow.com/a/13638931/570722 — Christian Benke, Jan 26 '17 at 09:25

score 6 · Answer 2 · answered Apr 23 '20 at 20:49

6

If you are using Python 3, simply do:

list(filter(None, your_list_name))

This removes all empty dicts from your list.

answered Apr 23 '20 at 20:49

CodeBiker

2,985
2
33
36

Christian Benke · Answer 3 · 2017-01-26T10:33:31.563

There's a even simpler and more intuitive way than filter, and it works in Python 2 and Python 3:

You can do a "truth value testing" on a dict to test if it's empty or not:

>>> foo = {}
>>> if foo:
...   print(foo)
...
>>>
>>> bar = {'key':'value'}
>>> if bar:
...    print(bar)
...
{'key':'value'}

Therefore you can iterate over mylist and test for empty dicts with an if-statement:

>>> mylist = [{'age': 25, 'job': 'teacher'}, {}, {}, {'age': 35, 'job': 'clerk'}]
>>> [i for i in mylist if i]
[{'age': 25, 'job': 'teacher'}, {'age': 35, 'job': 'clerk'}]

score 2 · Answer 4 · answered Aug 24 '15 at 11:19

2

This while loop will keep looping while there's a {} in the list and remove each one until there's none left.

while {} in dictList:
    dictList.remove({})

answered Aug 24 '15 at 11:19

SuperBiasedMan

9,814
10
45
73

score 1 · Answer 5 · answered Dec 13 '19 at 16:52

You may try the following function:

def trimmer(data):
    if type(data) is dict:
        new_data = {}
        for key in data:
            if data[key]:
                new_data[key] = trimmer(data[key])
        return new_data
    elif type(data) is list:
        new_data = []
        for index in range(len(data)):
            if data[index]:
                new_data.append(trimmer(data[index]))
        return new_data
    else:
        return data

This will trim

{
 "ages":[{"age":25,"job":"teacher"},
         {},{},
         {"age":35,"job":"clerk"}
        ]
}

and even

{'ages': [
    {'age': 25, 'job': 'teacher', 'empty_four': []},
    [], {},
    {'age': 35, 'job': 'clerk', 'empty_five': []}],
    'empty_one': [], 'empty_two': '',
    'empty_three': {}
}

to this: {'ages': [{'age': 25, 'job': 'teacher'}, {'age': 35, 'job': 'clerk'}]}

This solved my issue perfectly, either your dictionary is a list of dictionary or dictionary of dictionary. Considering, it should be accepted as an answer. Thanks — Houy Narun, Dec 02 '20 at 08:50

score 1 · Answer 6 · edited Nov 25 '21 at 05:54

1

You can also try this

mylist = [{'age': 25, 'job': 'teacher'}, {}, {}, {'age': 35, 'job': 'clerk'}]

mylist=[i for i in mylist if i]

print(mylist)

Output:

[{'age': 25, 'job': 'teacher'}, {'age': 35, 'job': 'clerk'}]

edited Nov 25 '21 at 05:54

Suraj Rao

29,388
11
94
103

answered Nov 25 '21 at 05:52

Sachin Sonigra

11
2

how to delete empty dict inside list of dictionary?

6 Answers6

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